Hi there,
To travel from Jamies house to the school, you would have to travel is 7km770m.
I hope my answer has satisfied your request and that you continue to use this website for your schooling.
Sincerely,
Dus4nR
1.) The sum(addition) of 21 and 5 times(multiplication) a number f is(=) 61.
f = unknown number/variable [So 21 plus 5f(5 times f) equals 61]
21 + 5f = 61 [21(one-time) + 5f(number x variable) = 61(total)]
2.) Seventeen more(addition) than seven times(multiplication) a number j is(=) 87.
j = unknown number/variable [So 17 plus 7j(7 times j) equals 87]
17 + 7j = 87
3.) n = number of calls
18 + 0.05n = 50.50
[Company charges $18 plus five cents per call(n), and the total charge was $50.50]
4.) s = the number of students
40 + 30s = 220
[Tutor charges $40 plus $30 per student(s), and the total charge was $220]
To add monomials, you have to look at the variables that are accompanied by their coefficients. In the given problem, (–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd), you can combine both cd ut nt cd and c² and cd and d and d and c² because they have different variables.
<span>(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)
(-4c</span>² + 8c²) + (7cd + 4cd) + (8d - 3d)
4c² + 11cd + 5d
Answer:
Step-by-step explanation:
d + q = 94.....d = 94 - q
0.10d + 0.25q = 19.30
0.10(94 - q) + 0.25q = 19.30
9.4 - 0.10q + 0.25q = 19.30
-0.10q + 0.25q = 19.30 - 9.40
0.15q = 9.90
q = 9.90/0.15
q = 66 <===== there are 66 quarters
d + q = 94
d + 66 = 94
d = 94 - 66
d = 28 <==== there are 28 dimes
