A14 is running toward the goal. her teammate, a12, kicks the ball toward a14. a14 did not see the ball coming and the ball strik
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Answer:
Therefore, the force supported by the hydraulic cylinder is = -70.01 lb
Thus, the force supported by the bar = -233.84 lb
The reaction force supported by the reaction of the roller = 341.31 lb
Explanation:
The attached diagrams is shown in the file below:
From there; taking moments about point A
- 40 (180) - (80) Cos 37° + 55
-7200 + (-80 Cos 37° + 55 sin 37° ) = 0
= - 7200 - 30.79
- 30.79 = 7200
=
= -233.84 lb
Thus, the force supported by the bar = -233.84 lb
Taking the equilibrium of forces in the vertical direction
sin 37 +
cos 20 -
= 0
- 233.84 sin 37 + cos 20 - 180 = 0
cos 20 = 320.73
=
= 341.31 lb
The reaction force supported by the reaction of the roller = 341.31 lb
Taking the equilibrium of forces on the horizontal direction.
cos 37 -
sin 20° = 0
-233.84 cos 37 - + 341.31 sin 20° = 0
-186.75 - + 116.74 = 0
- -70.01 = 0
- = 70.01
= - 70.01 lb
Therefore, the force supported by the hydraulic cylinder is = -70.01 lb
In electrical circuit, this arrangement is called a R-L series circuit. It is a circuit containing elements of an inductor (L) and a resistor (R). Inductance is expressed in units of Henry while resistance is expressed in units of ohms. The relationship between these values is called the impedance, denoted as Z. Its equation is
Z = √(R^2 + L^2)
Z = √((1.24×10^3 ohms)^2 + (6.95×10^-6 H)^2)
Z = 1,240 ohms
The unit for impedance is also ohms. Since the circuit is in series, the voltage across the inductor and the resistor are additive which is equal to 12 V. Knowing the impedance and the voltage, we can determine the maximum current.
I = V/Z=12/1,240 = 9.68 mA
But since we only want to reach 73.6% of its value, I = 9.68*0.736 = 7.12 mA. Then, the equation for R-L circuits is
, where τ = L/R = 6.95×10^-6/1.24×10^3 = 5.6 x 10^-9
Then,
t = 7.45 nanoseconds
Part B.) If t = 1.00τ, then t/τ = 1. Therefore,
I = 6.12 mA
Z = √(R^2 + L^2)
Z = √((1.24×10^3 ohms)^2 + (6.95×10^-6 H)^2)
Z = 1,240 ohms
The unit for impedance is also ohms. Since the circuit is in series, the voltage across the inductor and the resistor are additive which is equal to 12 V. Knowing the impedance and the voltage, we can determine the maximum current.
I = V/Z=12/1,240 = 9.68 mA
But since we only want to reach 73.6% of its value, I = 9.68*0.736 = 7.12 mA. Then, the equation for R-L circuits is
Then,
t = 7.45 nanoseconds
Part B.) If t = 1.00τ, then t/τ = 1. Therefore,
I = 6.12 mA