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Lynna [10]
3 years ago
8

Sabas dance class is 3 miles from her home

Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0
Ok what is the question so I can give you the answer
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What is the missing step in this proof
bagirrra123 [75]
Ok the parralelogram is 25 units and I think the angle of BCD would be 53. I got this by subtracting 127 from 180 since that should give you the whole square. and I got teh units by adding the lines BC and AB... Hope this helped
8 0
2 years ago
There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am
Bas_tet [7]

Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

n = 479, \pi = \frac{130}{479} = 0.2714

Hence the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 - 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.2316

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 + 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.3112

The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
2 years ago
A water balloon slingshot launches its projectiles essentially from ground level at a speed of 25.5 m/s . (You can ignore air re
lozanna [386]
A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.

B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.

Flight time = 2* ascendent time

ascendent time => final vertical velocity, Vy, = 0

sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s

Vy = Voy - gt = 0  => Voy = gt = t = Voy / g

Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)

t = 18.03 m/s / 10 m/s^2 = 1.83 s

This is the ascendant time going upward.

The flight time is 2*1.83 = 3.66 s

Horizontal motion

Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s

Vx = x / t => x = Vx*t

Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m

c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
5 0
3 years ago
Write an algorithm to solve the problem with long division. Answer in at least 3 complete sentences.​
Tamiku [17]

Answer:

1) Divide; 2) Multiply; 3) Subtract; 4) Drop down the next digit. Of these steps, #2 and #3 can become difficult and confusing to students

Step-by-step explanation:

7 0
2 years ago
HELP PLEASE!!
zhenek [66]

Answer:

y = 1/2x + 1.

Step-by-step explanation:

Use the point-slope form of a straight line:

y - y1 = m(x - x1)     (where m=slope and(x1,y1) is a point on line).

y - 3 = 1/2(x - 4)

y = 1/2x - 2 + 3

y = 1/2x + 1.

7 0
2 years ago
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