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Leviafan [203]
3 years ago
10

The length of a rectangle is 3 feet more than twice the width. The perimeter is 24 ft. Find the dimensions of the rectangle

Mathematics
1 answer:
pychu [463]3 years ago
8 0

The length is 9 and the width is 3. 3×2+3 is 9 and 3+3+9+9 is 24

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Answer: See the picture attached.

Step-by-step explanation:

Given the following mixed numbers:

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You need to convert them to decimal numbers. The steps to do this are shown below:

1. Divide the numerator of the fraction by the denominator.

2. Add the quotient obtained to the whole number part.

Then:

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8 0
3 years ago
I’m Really lost if I could get a answer it would be greatly appreciated
Nataly [62]
<h3>Answers:</h3>

f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}

================================================

Work Shown:

Part 1

f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out \left(\sqrt{x-1}+5\right)^2

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kap26 [50]

Answer:

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astra-53 [7]

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Let p(x) be the profit function.

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