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mestny [16]
2 years ago
10

Which equation represents a linear function rule for the following set of ordered pairs?

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
3 0

The equation that represents the linear function for the set of ordered pairs is: A. y = -3x + 2.

<h3>What is the Equation of a Linear Function?</h3>

Equation of a linear function, where m is the slope and b is the y-intercept, is expressed as y = mx + b.

Find the slope (m):

Slope (m) = change in y/change in x = (-7 -(-4)) / (3 - 2)

Slope (m) = -3/1 = -3

Find b by substituting m = -3 and (1, -1) = (x, y) into y = mx + b:

-1 = -3(1) + b

-1 = -3 + b

-1 + 3 = b

2 = b

b = 2

Substitute m = -3 and b = 2 into y = mx + b

y = -3(x) + 2

y = -3x + 2

Therefore, the equation that represents the linear function for the set of ordered pairs is: A. y = -3x + 2.

Learn more about equation of linear function on:

brainly.com/question/15602982

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The correct answer is:  [D]:  "  x² – 5x – 24 " .
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Explanation:
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Given:  " (x + 3)(x – 8) " ; expand :
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Note:  (a + b) (c + d) = ac + ad + bc + bd .
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   " (x + 3)(x – 8) " ; 

        =  (x * x)  + ( -8 * x)  + ( 3 * x ) + (3 * -8) ; 

        =  x² + (-8x) + 3x + (-24) ;

         = x² – 8x + 3x – 24 ;

→ Combine the "like terms" :

          – 8x  +  3x  =  – 5x ;

And simplify the expression; 

to get: 

→  " x² – 5x – 24 " ; which is:  Answer choice:  [D]:  " x² – 5x – 24 " .
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Suppose that the given line has a slope of -2/3 and a y-intercept of (0,5/3). which of the following points is also a solution t
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Answer:

From five given points it is find that points (1 , 1) and (4 , -1) will apply

Step-by-step explanation:

According to question,

Slop of line (m) = \frac{-2}{3}

And y-intercept is ( 0, \frac{5}{3})

So from above slope and points, the equation of line can be written as

y = mx + c

i.e \frac{5}{3} = \frac{-2}{3} x + c

    \frac{5}{3} = \frac{-2}{3} (0) + c

    \frac{5}{3} = 0 + c

Or, c = \frac{5}{3}

A) With points ( 5, \frac{5}{3} )

   At x = 5, y =\frac{-2}{3} (5) + \frac{5}{3}

            or, y = \frac{-10}{3} + \frac{5}{3}

            so, y = \frac{-5}{3}

Hence this points do not apply

B) With points ( 1 , 1 )

   At x = 1, y =  \frac{-2}{3} (1) +  \frac{5}{3}

      or,      y =  \frac{-2+5}{3}

      So,     y =  \frac{3}{3}

                y = 1

Hence this points will apply

C) With points ( 4 , -1 )

    At x = 4 , y =  \frac{-2}{3} (4) +  \frac{5}{3}

                    y =  \frac{-8+5}{3}

                    y =  \frac{-3}{3}

             So,  y= -1

Hence this points will apply

D) With points (-3 ,7)

    At x = - 3, y = \frac{-2}{3} (-3) +  \frac{5}{3}

                     y = \frac{14}{3}

 Hence this point will not apply

E) with points (0 , 0)

    At x 0,     y =  \frac{-2}{3} (0) +  \frac{5}{3}

               Or, y = 0 +  \frac{5}{3}

                     y =  \frac{5}{3}

Hence this point will not apply

∴ From above five given points it is find that points (1 , 1) and (4 , -1) apply

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