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marta [7]
3 years ago
6

What is the answer to this math equation? - 1 5/8 + 9 1/4

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
4 0
I think -4 something
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Which answer shows a correct order to solve this story problem?
Salsk061 [2.6K]
C is correct. 
1. You do 12.99 times 3
2. $0.69 times 2
3. Add $2.99 to the two prices above
4. Add the $2.52 tax to the prices
And you should get around $45 and some change
7 0
3 years ago
Can someone please help me find this answer.
Stels [109]

Answer:

-2x+4

Step-by-step explanation:

multiply all the components of the bracket by - 1.

then you arrive at the answer above

8 0
3 years ago
Please help! (image is for question 3)
nika2105 [10]

The formula for the total sum of the inner angles of the polygon is

Sn= (n-2) 180°

1) S6= (6-2) 180 = 4*180 = 720° In the hexagon all angles are equal

α= S6/6= 720/6= 120°

2) In each polygon the sum of the external angles is 360°

3) S5= (5-2) 180 = 540° than  we can add up all angles

x+131+108+107+110=540 => x= 540-456= 84°

4) α = 360/5=72°

Good luck!!!


6 0
3 years ago
Read 2 more answers
Find area of the figure. Round to the nearest hundredth if necessary.
Thepotemich [5.8K]
<span><span>
It would be 17.64 for the area</span></span>
8 0
3 years ago
What is the area of a triangle for one of the legs being 3in and the hypotenuse being 9in
elena55 [62]

The area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches is 12.727 square inches

<em><u>Solution:</u></em>

Given that to find area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches

From given information,

Let "c" = hypotenuse = 9 inches

Let "a" = length of one of the leg of triangle = 3 inches

To find: area of triangle

<u><em>The area of triangle when hypotenuse and length of one side of triangle is given:</em></u>

A = \frac{1}{2} a \sqrt{c^2 - a^2}

Where, "c" is the length of hypotenuse

"a" is the length of one side of triangle

Substituting the given values we get,

A = \frac{1}{2} \times 3 \times \sqrt{9^2 - 3^2}

A =\frac{1}{2} \times 3 \times \sqrt{81-9}\\\\A =\frac{1}{2} \times 3 \times \sqrt{72}\\\\A =\frac{1}{2} \times 3 \times 8.48528\\\\A = \frac{1}{2} \times 25.45584\\\\A = 12.727

Thus area of triangle is 12.727 square inches

5 0
3 years ago
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