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julia-pushkina [17]
3 years ago
15

BRAINLIST IF YOU ANSWER THIS RIGHT THE FIRST PERSON TO GET IT RIGHT GETS IT

Mathematics
2 answers:
Aleks [24]3 years ago
7 0

Answer:

25.5

Step-by-step explanation:

Hope this helps!

SVETLANKA909090 [29]3 years ago
3 0

Answer:

The height would be  25.5 or 25 1/2

Step-by-step explanation:

You use the area of the triangle, in this case 471.75 and divide it by 18.5 and you get 25 1/2.

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10. Which of the following situations represents a proportional relationship?....
tia_tia [17]

Answer:

G  A pool fills at a rate of 90 gallons per hour

Step-by-step explanation:

i dont know

7 0
2 years ago
Complete the table and draw the graph
Neko [114]

Answer:

So the vaule of y is 7, 10 & 13

Step-by-step explanation:

Given that y = 3x+1 . So we can just substitute x-value into the equation :

Let x=2,

y = 3(2)+1

= 7

Let x=3,

y = 3(3)+1

= 10

Let x=4,

y = 3(4)+1

= 13

5 0
3 years ago
Three friends each bought two slices of pizza and a drink at the mall. If drinks cost $0.75 and the total of their order was $11
monitta

Answer:

I believe it's $1.50

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which theorem or postulate proves that △ABC and △DEF are similar?
yan [13]

Answer:

△ABC and △DEF are similar by SAS Similarity Theorem.

Option (C) is correct .

Step-by-step explanation:

Definition of SAS Similarity property

Two triangles are said to be similar by SAS Similarity property If two sides are proportional and one corresponding angle congruent .

In △ABC and △DEF

\frac{ED}{AB}= \frac{7}{21}

\frac{ED}{AB}= \frac{1}{3}

and

\frac{EF}{BC}= \frac{11}{33}

\frac{EF}{BC}= \frac{1}{3}

Thus

\frac{ED}{AB}=\frac{EF}{BC}= \frac{1}{3}

∠ABC = ∠DEF  (As given in the figure )

Thus △ABC and △DEF are similar by SAS Similarity property .

7 0
3 years ago
Read 2 more answers
You throw two four-sided dice. Let the random variable X represent the maximum value of the two dice. Compute E(X). Round your a
Troyanec [42]

Answer:

E(X)=3.125

Step-by-step explanation:

We are given that two four sided dice.

Then , the sample space

{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)}

Total number of outcomes=16

Let the random variable X represent the maximum value of the two dice

Outcomes                            X                                 P(X)

(1,1)                                          1                                 1/16

(1,2),(2,1),(2,2)                                   2                        3/16

(1,3),(2,3),(3,1),(3,2),(3,3)                    3                           5/16  

(1,4),(3,4) ,(2,4),(4,1),(4,2),(4,3),(4,4)    4                            7/16

Using the probability formula

P(E)=\frac{Favorable\;outcomes}{Total\;number\;of\;outcomes}

Now,

E(X)=\sum_{i=1}^{n}x_iP(x_i)

E(x)=1(1/16)+2(3/16)+3(5/16)+4(7/16)

E(x)=\frac{1+6+15+28}{16}

E(x)=\frac{50}{16}=3.125

7 0
3 years ago
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