Bob got 8 presents 1/2 flew away how many do he have?

A container shaped as a rectangular prism can hold 756 wooden cube blocks with edge lengths of 1/3 ft

zhuklara [117]

The answer is 252 ft3 because logically if the cubes had a length of one foot, the rectangular prism would be 756 feet, so you would just divide that number by three considering that the cubes are only 1/3 of a foot.
Hope this helps !!
Feel free to ask any questions :)

3 0

3 years ago

Question 17 (1 point)

jekas [21]

Answer:

3x

Step-by-step explanation:

8 0

3 years ago

Whats equivalent to 14(8−6x+12)

iren2701 [21]

We can use the distributive property to set up an expression that is equal to this problem.

14 times 8 is 112
14 times -6 is -84x
14 times 12 is 168
(If you don't know the distributive property ask and I can explain it)

We can combine that together to get:

112 +168 -84x
Or, condense it further:

280-84x is equivalent to 14(8-6x+12)

8 0

4 years ago

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Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

4 years ago

Let u= (-1,3) and w =(2,4) Find the resulting vector of 2u-4w in component form..

IgorLugansk [536]

Very simple. You just use the vectors as normal numbers, and multiply the coordinates with 2 and 4 like this:

2*u = 2* (2,4) = (4,8)
4*w = 4* (-1,3) = (-4,12)

(4,8) - (-4,12) = (8,-4)

So the vector has the coordinates (8,-4)

7 0

4 years ago

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