Sheila eats 3/4 of a bag of baby carrots each week.How many bags of carrots does she eat in 6 weeks? Write in Simplest Form

Mathematics

2 answers:

telo118 [61]3 years ago

6 0

Answer:

9/2

Step-by-step explanation:

Ivanshal [37]3 years ago

5 0

9/2
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Thee population of a town, P(t), is 2000 in the year 2010. Every year, it increases by 1.5%. Write an equation for the populatio

steposvetlana [31]

Given:

In 2010, the population of a town = 2000

Every year, it increase by 1.5%

To find the equation P(t) which represents the population of this town t years from 2010.

Formula

If a be the original population of a town and it increases by b% every year, after t year the population will be

$a (1+\frac{b}{100} )^{t}$

Now,

Taking, a =2000, b = 1.5 we get,

$P(t) = 2000(1+\frac{1.5}{100} )^{t}$

or, $P(t) = 2000(1+0.015)^{t}$

Hence,

The population of this town t years from 2010 P(t) = $2000(1+0.015)^{t}$ , Option D.

7 0

3 years ago

Please help me with this problem..

charle [14.2K]

Answer:

y = 6

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 3 when x = 9, then

k = $\frac{y}{x}$ = $\frac{3}{9}$ = $\frac{1}{3}$ , thus

y = $\frac{1}{3}$ x ← equation of variation

When x = 18, then

y = $\frac{1}{3}$ × 18 = $\frac{18}{3}$ = 6

5 0

3 years ago

I REALLY NEED HELP!

anastassius [24]

$\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$3700\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ t=years\dotfill &7 \end{cases} \\\\\\ A=3700e^{0.045\cdot 7}\implies A=3700e^{0.315}\implies A\approx 5069.96$