Answer:
(x-y)(x-y-3)
Step-by-step explanation:
(x-y)² - 3(x-y)
take (x-y) common,
(x-y)(x-y-3)
5x + y = 9....multiply by 7
10x - 7y = -18
----------------
35x + 7y = 63 (result of multiplying by 7)
10x - 7y = -18
----------------add
45x = 45
x = 45/45
x = 1
5x + y = 9
5(1) + y = 9
5 + y = 9
y = 9 - 5
y = 4
solution is : (1,4)
=========================
-4x + 9y = 9
x - 3y = -6 ....multiply by 4
----------------
-4x + 9y = 9
4x - 12y = -24 (result of multiplying by 4)
---------------add
- 3y = - 15
y = -15/-3
y = 5
x - 3y = -6
x - 3(5) = -6
x - 15 = -6
x = -6 + 15
x = 9
solution is : (9,5)
Answer:
76.16 kilograms of food
Step-by-step explanation:
Number of cyclist = 32
Food per cyclist = 8.33 kilograms
Days of the trip = 7 days
Food per cyclist per day = 8.33 kg / 7
= 1.19kg food per day for each cyclist
how many kilograms of food will the group be carrying at the end of Day 5?
5 days out of 7 days = 2 days
Each cyclist will have to carry = 2 × 1.19 kg of food for the remaining two days
= 2 × 1.19
= 2.38 kilograms of food for two days
32 cyclist for 2 days = 32 × 2.38 kg of food
= 76.16 kilograms of food
The group will be carrying 76.16 kilograms of food at the end of Day 5
Answer:
6
Step-by-step explanation:
10/5 ×/3 multiply 10×3 and than divide by 5
or another way start with multiplying 5 and n equaling 5n=
than 10× 3= 30 so you're left with 5n=30 divied 30 by 5 equalling 6
so x=6
Answer:
5510.4
Step-by-step explanation: