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nlexa [21]
3 years ago
9

123 times 60 __________ equals 1,480 A. True B. False

Mathematics
1 answer:
Lorico [155]3 years ago
3 0
123x60=7,380

So, the answer is B. False

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Explain your answer !!<br><br> Will give brainlst
blagie [28]

Answer:

(-2, 2)

Step-by-step explanation:

this is the point where y= -2x+1 meets y=2x+3

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HELP ME !!! PLEASE SOMEONE
UkoKoshka [18]

Answer:

The sequence is step 7, 9, 1, 4, 2, 8

Step-by-step explanation:

They give us a series of steps to organize the operation of the inverse of the function y = (x-4) / (33-x)

they give us 9 steps, which 3 are incorrect since it is only done in 6 steps.

1. The first step is step # 7

It is the exchange of variables, it would be:

x = (y -4) / (33 - y)

2. The second step is step # 9

the denominator (33-y) is multiplied by x, like this:

x * (33 - y) = y -4

3. The third step is step # 1

Multiply the x by 33 - y, like this:

33 * x - x * y = y - 4

4. The fourth step is step # 4

We rearrange the equation:

33 * x + 4 = y + x * y

5. The fifth step is step # 2

We take common factor "and"

33 * x + 4 = y * (1 + x)

6. The sixth and last step is step # 8

We solve for "y", that is, we pass divide (1 + x) and it would be:

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3 years ago
What is the sum of negative 8/19 and negative 4/57
DedPeter [7]

Answer:

I can only guess that your answer is 32/1083.

Step-by-step explanation:

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3 years ago
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Solve B=1/4m(s+z) for s
ElenaW [278]

Answer:

s = \frac{-mz+4B}{m}

Step-by-step explanation:

Step 1: Distribute.

  • B = \frac{1}{4}m * s + \frac{1}{4}m * z
  • B = \frac{1}{4}ms + \frac{1}{4}mz
  • \frac{1}{4}ms + \frac{1}{4}mz = B

Step 2: Subtract 1/4(mz) from both sides.

  • \frac{1}{4}ms + \frac{1}{4}mz - \frac{1}{4}mz = B - \frac{1}{4}mz
  • \frac{1}{4}ms = -\frac{1}{4}mz + B

Step 3: Divide both sides by m/4.

  • \frac{1}{4}ms/\frac{m}{4}=(\frac{-1}{4}mz + B)/\frac{m}{4}
  • s = \frac{-mz+4B}{m}
6 0
3 years ago
How many solutions does the equation-5a+5a+9=8 have
Dominik [7]
It has zero solutions because -5a+5a= 0, and 9 does not equal zero, so there are no solutions.
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