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Snezhnost [94]
3 years ago
7

Help ASAP!! I’m confused and need help. Thanks!!

Mathematics
2 answers:
LiRa [457]3 years ago
6 0
It is an acute angle.

Acute angles measure less than 90 degrees. Right angles measure 90 degrees. Obtuse angles measure more than 90 degrees.
zhuklara [117]3 years ago
3 0
This degree of angle 1 is an Acute angle
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Anyone please help me
Verdich [7]
9) Original price: $45 ; discount rate : 20% off
Discount     = $45 * 20%   =   $9
Sales price = $45 - $9       = $36

10) Original price : $450 ; discount rate : 30% off
Discount     = $450 * 30%  = $135
Sales price = $450 - $135 = $315

11) Original price : $48 ; discount rate : 15% off
Discount     =  $48 * 15%  =   $7.20
Sales price = $48 - $7.20 = $40.80

12) Original price : $150 ; discount rate : 25% off
Discount     = $150 * 25%      =   $37.50
Sales price = $150 - $37.50 = $112.50

13) Original price : $1,450 ; discount rate : 40% off
Discount     = $1,450 * 40%  = $580
Sales price = $1,450 - $580 = $870

14) Original price : $82 ; discount rate : 50% off
Discount     = $82 * 50% = $41
Sales price = $82 - $41  = $41
4 0
3 years ago
Sheila turned on two buzzers at the
kozerog [31]
5 times because 60÷12 = 5
8 0
3 years ago
Pweez take a look <3 PLEASEEEEEEEEEE
aleksandr82 [10.1K]

Your answers are FWR and QET because they are on the same lines. Remember that the prefix co = same. Hope this helps.

4 0
3 years ago
Read 2 more answers
Lynette can wash 95 cars in 5 days how many cars can she wash in 11 days​
STatiana [176]

Find how many cars she can wash in one day:

95 cars / 5 days = 19 cars per day.

Now multiply by 11 days:

19 cars per day x 11 days = 209 total cars.

7 0
3 years ago
Help with num 4 please.​
kati45 [8]

Answer:

y=1/2(x-1)

Step-by-step explanation:

If x=t^2 and t>0, then t=sqrt(x).

If t=sqrt(x) or x^(1/2) and y =1-1/t, then y=1-x^(-1/2).

The x-intercept is when y=0.

So we need to solve 0=1-x^(-1/2) to find point P.

Add x^(-1/2) on both sides: x^(-1/2)=1.

Raise both sides to -2 power: x=1

So point P is (1,0).

Let's find tangent line at point (1,0).

We will need the slope so let's differentiate.

y'=0+1/2x^(-3/2)

y'=1/(2x^(3/2))

The slope at x=1 is y'=1/(2[1]^(3/2))=1/(2×1)=1/2.

Recall point-slope form is y-y1=m(x-x1).

So our line we are looking for is y-0=1/2(x-1)

Let's simplify left hand side y=1/2(x-1)

4 0
4 years ago
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