We know that 1 and 6 are supplementary because 1 and 5 are corresponding angles. 5 and 6 are supplementary angles. Since 1 and 5 are corresponding & 5 and 6 are supplementary angles, 1 and 6 will also be supplementary.
Have a nice day!
If this is not what you are looking for - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
Answer:
1.09×10^2
Step-by-step explanation:
................
Answer:
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.
Each minute has 60 seconds, so 
Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

We want
. So
In which


0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Answer:
Jada error was he multiplied the equation by (-9/4) to make the coefficient of x one. He should have multiplied it by 108
Step-by-step explanation:
Jada solved the equation
-4/9 = x/108
using the steps below:
-4/9 = x/108
(-4/9)(-9/4) = (x/108)(-9/4)
x = -1/48
Jada should have multiplied through by 108, instead of (-4/9). That was the error he made.
Multiplying through by 108 gives
(-4/9)(108) = (x/108)(108)
-48 = x
x = -48
The answer should have been
x = -48
and not
x = -1/48
Answer:
Step-by-step explanation:
we know that
The compound interest formula for this problem is equal to
where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods in years
in this problem we have
substitute in the formula above