k = 4pq^2 //Divide both sides by 4p
k/4p = q^2 //Square root on both sides
+- √(k / 4p) = q
q = √k / 2√p and - √k / 2√p
You can’t make another Square because you can’t multiply number that give you 23
First you have to put it into slope intercept form. You have to put it into y = mx + b then m is the slope and b is the y intercept on the graph.
The y-intercept of the graph shows that at m = 0, c = 15. We can see a constant slope that causes the graph to pass through m = 20, c = 20, as well as m = 40, c = 25. This shows a constant increase of $5/20 minutes, or a slope of 5/20 = 1/4. Based on slope-intercept form y = mx+b, the equation would be c = (1/4)m+15, from 0 <= m <= 44,640. This is the second of the given choices.
No, it is not a solution.
Let's plug 5 into the equation where p is.
10(5) - 2 > 97
50 - 2 > 97
48 > 97
This is false, 48 is less than 97.
