9x + 9 + 2x - 7(3 + x) =

Ben earns $12,800 a year. About 15% is taken out for taxes. How much is taken out for taxes?

lesya692 [45]

Answer:

$10880

Step-by-step explanation:

12800-15%=10880

5 0

3 years ago

-9s - 8 = -4s + 8 - 3s

Olenka [21]

I wont solve this because Im to lazy, but I do recommend some of these sites to help you with your problem. MathPapa Algebra Calculator and PhotoMath. Hope this helps.

4 0

4 years ago

Read 2 more answers

A point is located in quadrant II of a

givi [52]

Answer:

Choose a point with a negative x coordinate and a positive y coordinate.

Step-by-step explanation:

The quadrants are labeled counter clockwise 1, 2, 3, and 4.

Quadrant I - has x and y coordinate both positive.

Quadrant 2 - has x coordinate negative and y coordinates positive.

Quadrant 3 - has x and y coordinates both negative.

Quadrant 4 - has x coordinates positive and y coordinates negative.

Since the point is in quadrant 2, choose a point where x is negative but y is positive like (-3, 2).

3 0

3 years ago

Will give 100 pts and brainliest

prohojiy [21]

Answer:

y = $\sqrt{19^2 + 8.2^2}$

Step-by-step explanation:

to get the hypotenuse:

use the Pythagorean theorem:

a² + b² = c²

where a = 19, b = 8.2 c = y

plugin values:

19² + 8.2² = y²

y = $\sqrt{19^2 + 8.2^2}$

8 0

3 years ago

Read 2 more answers

Suppose a poll is taken that shows that 765 out of 1500 randomly selected, independent people believe the rich should pay more

Zanzabum

Answer:

$z=\frac{0.51 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1500}}}=0.775$

$p_v =P(z>0.775)=0.219$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly higher than 0.5

Step-by-step explanation:

Data given and notation

n=1500 represent the random sample taken

X=765 represent the successes

$\hat p=\frac{765}{1500}=0.51$ estimated proportion of successes

$p_o=0.5$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:

Null hypothesis: $p \leq 0.5$

Alternative hypothesis: $p > 0.5$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.51 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1500}}}=0.775$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>0.775)=0.219$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly higher than 0.5

8 0

3 years ago