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3 years ago

D=f+ fx solve for x

Mathematics

1 answer:

Zepler [3.9K]3 years ago

3 0

Answer:

X = d/f - 1

Step-by-step explanation:

You would Isolate the variable by dividing each side by factors that don't contain the variable. Hope this helps

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Olin [163]

Answer:

Step-by-step explanation:

X is 1 y is -4

Which gets the following:

X(1) + y(-4) = -3

x(1) + 2(-4) = -7

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3 years ago

Read 2 more answers

In the triangle below,

Fynjy0 [20]

Step-by-step explanation:

4x -20 + 3x +12 = 90

7x -8 = 90

7x = 98

x = 14

Angle F: 4(14) -20 = 36

Angle E: 3(14)+12= 54

Angle G : 90

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3 years ago

Stacy fails 1/2 cup measuring cup seven times to have enough flour for cake recipe how much flour does the cake recipe call for

Gala2k [10]

7 times of 1/2 cup = 7 x 1/2
7 times of 1/2 cup = 7/2
7 times of 1/2 cup = 3 1/2 cups.

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The recipe called for 3 1/2 cups of flour
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3 years ago

How do you find the area of each regular polygon

Alex73 [517]

If the drawing of your octagon (or whatever) has been separated into triangles, and one triangle's area is labeled, then you do not need to know the apothem. Just take the area of that one triangle, and multiply by the number of sides in the original polygon.

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3 years ago

Find sinϴ and cosϴ if tanϴ=1/4 and sinϴ>0

eduard

If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701

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$\mathsf{tan\,\theta=\dfrac{1}{4}\qquad\qquad(sin\,\theta\ \textgreater \ 0)}\\\\\\
\mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{1}{4}}\\\\\\
\mathsf{4\,sin\,\theta=cos\,\theta\qquad\quad(i)}$

Square both sides:

$\mathsf{(4\,sin\,\theta)^2=(cos\,\theta)^2}\\\\
\mathsf{4^2\,sin^2\,\theta=cos^2\,\theta}\\\\
\mathsf{16\,sin^2\,\theta=cos^2\,\theta\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{16\,sin^2\,\theta=1-sin^2\,\theta}$

$\mathsf{16\,sin^2\,\theta+sin^2\,\theta=1}\\\\
\mathsf{17\,sin^2\,\theta=1}\\\\
\mathsf{sin^2\,\theta=\dfrac{1}{17}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{1}{17}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{1}{\sqrt{17}}}$

Since $\mathsf{sin\,\theta}$ is positive, you can discard the negative sign. So,

$\mathsf{sin\,\theta=\dfrac{1}{\sqrt{17}}\qquad\quad\checkmark}$

Substitute this value back into $\mathsf{(i)}$ to find $\mathsf{cos\,\theta:}$

$\mathsf{4\cdot \dfrac{1}{\sqrt{17}}=cos\,\theta}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{\sqrt{17}}\qquad\quad\checkmark}$

I hope this helps. =)

Tags: trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus

7 0

3 years ago