Question

HELPPP PLZZZ

Answer 1

Answer:

Step-by-step explanation:

Given: A square tabletop has an area of $(9x^2-90x+225)cm^2$.The dimensions of the tabletop have the form cx-d, where c and d are whole numbers.

To find: Expression for the perimeter of the tabletop and the perimeter when x=25 centimeters.

solution: Since, we know that area of square =$(side)^2$, and we are given Area=$(side)^{2}$=$9x^2-90x+225$

⇒$s^{2}=(3x-15)(3x-15)$

⇒$s^2=(3x-15)^2$

⇒$s=3x-15$

Thus, side=$3x-15$.

Now, Perimeter of square is given as =4s

⇒$4s=4(3x-15)=12x-60$ which is the required expression for the perimeter.

Perimeter when x=25cm, $12x-60=12(25)-60=300-60=240cm$.

Therefore, Perimeter=240 cm.