Question

What is the area of a triangle whose vertices are R(−4,2) , S(1,2) , and T(−5,−4)?

Answer 1

Fisrt is solve the distance of the segments using distance formula

Distance =sqroot[(x2−x1)^2+(y2−y1)^2]

So ditance of RS = 5

ST = 8.49

TR =6.08

The using herons formula

Area = sqrt ( s ( s-a) ( s-b) ( s-c) )

Where s s = 1/2 ( a + b + c )

And a, b , c are length of the sides

S = 9.785

Area = 14.99