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Umnica [9.8K]
3 years ago
13

Please help me with my question:))

Mathematics
2 answers:
sergey [27]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Two lines are perpendicular when the product of their slopes = - 1

line 1: y = 3x + 4

(3 , 0)  ; (-3,2)

slope=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{2-0}{-3-3}\\\\=\frac{2}{-6}\\\\=\frac{-1}{3}

Slope of line 1 = 3

Slope of line 2 = -1/3

3* -1/3 = -1

MAVERICK [17]3 years ago
5 0

Answer:

im sorry but you just need a chill pill

Step-by-step explanation:

You might be interested in
Sue had 5 identical bags of candy to share with the crew. Twenty-five pieces of candy disappeared. Ted had 4 bags with the same
inna [77]

Answer:

Each bag originally had 35 pieces of candy

Step-by-step explanation:

Since the bags are identical, Let them Number of candies in each bag sue had be x. Thus, she had 5x candies. Since she lost 25 pieces, then she now has;

5x - 25 candies left.

We are told that Ted had 4 bags with the same number of candies like Sue had. Thus, he has 4x candies.

He mysteriously found 10 additional pieces. Total Ted now has is;. 4x + 10

Finally, we are told that Sue and Ted now have an equal number of candies.

Thus;

5x - 25 = 4x + 10

Rearranging, we have;

5x - 4x = 25 + 10

x = 35

Thus, each bag originally had 35 pieces of candy

3 0
3 years ago
At sea level, earths atmosphere exerts a pressure of 1 atmosphere. Atmospheric pressure P (in atmospheres) decreases with altitu
PtichkaEL [24]

Answer:

Initial Amount=1

Decay Factor=0.99987

Decay Rate=0.013%

Step-by-step explanation:

If P = 0.99987ᵃ

I. Initial amount

The initial amount is when a=0

P = 0.99987⁰ = 1

The Pressure at Sea Level=1

II. Decay factor

This is like the decay constant. From the model, P = 0.99987ᵃ, the decay constant/factor is 0.99987.

III. Decay Rate = 1-0.99987 = 0.00013

Expressed in Percentage = 0.013%

5 0
3 years ago
Read 2 more answers
(Fractions) Rewrite the expression using fithteenths. 2/5 - 1/3 =
Anastasy [175]

Answer:

1/15

Step-by-step explanation:

2/5-1/3=6/15-5/15=1/15

6 0
3 years ago
What is the slope of graph Pls Help
Zielflug [23.3K]

Answer:

The slope is 1/2

i believe

Step-by-step explanation:

Use the rise/run method

7 0
3 years ago
In a certain clinical study, 15% of participants were classified as heavy smokers, 25% as light-smokers, and the rest as non-smo
Natasha_Volkova [10]

Answer:

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

Step-by-step explanation:

We have the following probabilities:

A 15% probability that a participant is classified as a heavy smoker.

A 25% probability that a participant is classified as a light smoker.

A 100% - 25% - 15% = 60% probability that a participant is classified as a non smoker.

A x% probability that a non smoker dies.

A 3x% probability that a light smoker dies.

A 5x% probability that a heavy smoker dies.

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

This problem is:

What is the probability of the participant being a non-smoker, given that he died?

P(B) is the probability that the participant is a non smoker. So

P(B) = 0.6

P(A/B) is the probability that the participant dies, given that he is a non smoker. So:

P(A/B) = x

P(A) is the probability that the participant dies:

P(A) = P_{1} + P_{2} + P_{3}

P_{1} is the probability that a heavy smoker is selected and that he dies. So:

P_{1} = 0.15*5x = 0.75x

P_{2} is the probability that a light smoker is selected and that he dies. So:

P_{2} = 0.25*3x = 0.75x

P_{3} is the probability that a non-smoker is selected and that he dies. So:

P_{3} = 0.60*x = 0.60x

The probability that a participant dies is:

P(A) = P_{1} + P_{2} + P_{3} = 0.75x + 0.75x + 0.60x = 2.10x

The probability of the participant being a non-smoker, given that he died, is:

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.6x}{2.10x} = \frac{0.6}{2.10} = 0.2857

There is a 28.57% probability that a randomly selected participant who died by the end of the study was a non-smoker.

7 0
3 years ago
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