So you need to come up with a perfect square that works for the x coefficients.
like.. (2x + 2)^2
(2x+2)(2x+2) = 4x^2 + 8x + 4
Compare this to the equation given. Our perfect square has +4 instead of +23. The difference is: 23 - 4 = 19
I'm going to assume the given equation equals zero..
So, If we add subtract 19 from both sides of the equation we get the perfect square.
4x^2 + 8x + 23 - 19 = 0 - 19
4x^2 + 8x + 4 = - 19
complete the square and move 19 over..
(2x+2)^2 + 19 = 0
factor the 2 out becomes 2^2 = 4
ANSWER: 4(x+1)^2 + 19 = 0
for a short cut, the standard equation
ax^2 + bx + c = 0 becomes a(x - h)^2 + k = 0
Where "a, b, c" are the same and ..
h = -b/(2a)
k = c - b^2/(4a)
Vertex = (h, k)
this will be a minimum point when "a" is positive upward facing parabola and a maximum point when "a" is negative downward facing parabola.
i would say c is the best answer or the 3rd one
Answer:
12/13
Step-by-step explanation:
Given that MN = 5, NO = 12, and MO = 13, find cos O.
Since the reference angle is P, hence;
MN is the opposite = 5
MO is the hypotenuse = 13 (longest side)
NO is the adjacent = 12
Cos O = adj/hyp
Substitute the given values
Cos O = 12/13
Hence the value of Cos O is 12/13
Answer:i dont know
Step-by-step explanation:
-15 i think if not u just got to use the quadratic formula.
