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aliina [53]
4 years ago
11

Demonstrate how you can use the slope formula to write the point-slope form of an equation of a line.

Mathematics
1 answer:
nevsk [136]4 years ago
5 0
This is how I did it.

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Which ratio is porportional to 18/21? A.2/3 B. 30/35 C. 36/48 D.1/3
defon
You can solve this problem by applying the proccedure below:
 
 You have:
 
 a) 18/21=2/3
 18x3/21x2
 36≠42 (2/3 is not proportinal to 18/21).
 
 b)18/21=30/35
 18x35/21x30
 630=630  (30/35 is proportional to 18/21)
 
 c)18/21=36/48
 18x48/21x36
 864≠756  (36/48<span> is</span><span> not proportinal to 18/21)
</span> 
 d)18/21=1/3
 18x3/21x1
 54≠21  (<span> 1/3 is</span><span> not proportinal to 18/21)
</span> 
 Therefore, you can conclude that the correct option is: B.30/35
8 0
3 years ago
ZE and ZF are vertical angles with mZE = 8x + 8 and mZF = 2x +38.<br> What is the value of x?
Dovator [93]

Answer:

Since ZE and ZF are vertical angles, they are congruent.

8x+8 = 2x+38

8 = 2x-8x+38

8 = -6x+38

8-38 = -6x

-30 = -6x

x = -30/-6

x = 5

7 0
3 years ago
Read 2 more answers
Write an inequality to represent the following statement.
harina [27]
X<2.5

Don't forget to vote brainliest and follow me!!!
5 0
3 years ago
The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va
Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore

4 0
4 years ago
POSSIBLE
Nutka1998 [239]
The answer to your problem is x=26
7 0
3 years ago
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