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3 years ago

What is the conversion factor to convert cups to liters?

Mathematics

1 answer:

Gemiola [76]3 years ago

3 0

Answer:

0.2365882365 L/cup

Step-by-step explanation:

The conversion factor can be found from the size of a cup in relation to a gallon, and the size of a cubic inch in relation to a liter.

$1\,\text{cup}=8\,\text{fl oz}\times\dfrac{231\,in^{3}}{128\,\text{fl oz}}\times\left(\dfrac{0.254\,\text{dm}}{1\,\text{in}}\right)^{3}\times\dfrac{1\,L}{1\,dm^{3}}\\\\=\dfrac{8\cdot 231\cdot 0.254^{3}}{128}\,L=0.2365882365\,L$

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mel-nik [20]

If the length is two times its width and its perimeter is 36cm. we can write the following equation
let the width be X.
so the equation will be:
(X + 2X)2=36cm or
2X + 4X=36cm

3 0

4 years ago

A rectangular container that measures 2 cm x 11 cm x 20 cm is completely filled with water. The water is then poured into a holl

maksim [4K]

Answer:

14cm

Step-by-step explanation:

formula of a rectangular container is LBH and we were given that LBH is 2*11*20 which is equal to 440cm.

Now when the water is transferred into a hollow cylindrical container.the formula for that is 2pierh.440=2*22/7*5*h

440*7=220h

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1 year ago

Read 2 more answers

What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

4 years ago

Read 2 more answers

Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F'G'H'I': Hexagon DEFGHI and Hexagon D prime E

MatroZZZ [7]

<span>(x, y)→(x − 8, y − 7) is the correct translation. Take point D for example. The coordinate of D is (2, 5). The coordinate of D' (after translation) is (-6, -2). Since 2-8=-6, 5-7=-2, only the first choice is correct. You can also try other points and see why only this is the right translation.</span>

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3 years ago

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What is i^22 if i^2 is -1

Sever21 [200]

I^22 equals to -1 since i^2 is negative one

4 0

2 years ago