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soldi70 [24.7K]
3 years ago
13

Which of these situations would best be represented using a quadratic function: the distance driven on a road trip, the path of

a tennis ball hit over the net, or the path of a train on train tracks? Explain why you chose your answer.
Mathematics
1 answer:
melamori03 [73]3 years ago
7 0
Quadratics have the parabola shape.  The distance driven on a road trip and the path of a train on train tracks can be represented linearly.

The path of a tennis ball can be represented by a quadratic function.  
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3x-y=1;d:{-3,-1,0,4}
Maslowich
First, rearrange the equation so that it is solving for y:
3x - y = 1
     +y   +y
3x = y + 1
-1         -1
3x - 1 = y
Now substitute the domain values you have listed into the 'x' of the equation to get the values for y.
For example:
3(-3) - 1 = y
-9 - 1 = y
y = -10
8 0
3 years ago
mr. ronaldo earns 54,800 annually. if his income tax rate is 9% then how much did he pay in income tax
Alik [6]

Answer:

Mr Ronaldo paid $4,932 in income tax

Step-by-step explanation:

In this question, we are asked to calculate the amount Mr Ronaldo pays in income tax

To calculate this, we need to calculate 9% of his annual earnings

His income tax = 9/100 * 54,800

Income tax = $4,932

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3 years ago
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galina1969 [7]

Answer:

A.

Step-by-step explanation:

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6 0
2 years ago
Totsaken sold half of his comic books and bought ten more. He now has 40. With how many did he begin?
AURORKA [14]
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8 0
2 years ago
Read 2 more answers
Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel
Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

\frac{40}{400}=0.10

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

P(X=x)=^nC_xp^x(1-p)^{n-x}

We need to find P(X ≤ 3)

P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\

P(X\leq3) =0.944444369992\approx 0.94

Hence, the required probability is 0.94

4 0
2 years ago
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