135 miles / 45mph = 3 hours
i hope this helps!
The delivery person will use 6 gallons of gasoline
The function to determine the number of miles in x hours is:
f(x) = x² + 3x
The number of gallons of gasoline used for driving y miles is:
g(y) = y/18
For a delivery person that works a 9-hour shift:
x = 9
f(9) = 9² + 3(9)
f(9) = 81 + 27
f(9) = 108
That is, the number of miles, y = 108 miles
The number of gallons of gasoline used:
g(y) = y/18
g(108) = 108/18
g(108) = 6
The delivery person will use 6 gallons of gasoline
Learn more here: brainly.com/question/16155213
According to my calculations the answer is 13/25 hope this helps
Answer: The graph is stretched.
Step-by-step explanation:
We have been given that in the morning an iceberg weighed 380,000 pounds. It lost 0.3% of its weight during the day. We are asked to find the weight of the ice-berg at the end of the day.
The weight of the ice-berg at the end of the day would be original weight of ice-berg minus 0.3% of original weight.
![\text{The weight of the ice-berg at the end of the day}=380,000-380,000\times \frac{0.3}{100}](https://tex.z-dn.net/?f=%5Ctext%7BThe%20weight%20of%20the%20ice-berg%20at%20the%20end%20of%20the%20day%7D%3D380%2C000-380%2C000%5Ctimes%20%5Cfrac%7B0.3%7D%7B100%7D)
![\text{The weight of the ice-berg at the end of the day}=380,000-3800\times 0.3](https://tex.z-dn.net/?f=%5Ctext%7BThe%20weight%20of%20the%20ice-berg%20at%20the%20end%20of%20the%20day%7D%3D380%2C000-3800%5Ctimes%200.3)
![\text{The weight of the ice-berg at the end of the day}=380,000-1140](https://tex.z-dn.net/?f=%5Ctext%7BThe%20weight%20of%20the%20ice-berg%20at%20the%20end%20of%20the%20day%7D%3D380%2C000-1140)
![\text{The weight of the ice-berg at the end of the day}=378,860](https://tex.z-dn.net/?f=%5Ctext%7BThe%20weight%20of%20the%20ice-berg%20at%20the%20end%20of%20the%20day%7D%3D378%2C860)
Therefore, the weight of the ice-berg at the end of the day would be 378,860 pounds.