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Lorico [155]
3 years ago
15

What is the radius of circle O

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0

Answer:

8.5 units

Step-by-step explanation:

first we gotta find the length of the diameter. they made it into a triangle, so we can use pythagorean theorem.

15² + 8² = c²

225 + 64 = c²

289 = c²

17 = c

so now we know that the length of the diameter is 17 units, so the radius would be half of that.

17 ÷ 2 = 8.5

so the radius is 8.5

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2x²-26x+84 (Factor COMPLETELY)
Nadya [2.5K]

\tt{} {2x}^{2}  - 26x + 84

\tt{}2 {(x}^{2}  - 13x + 42)

\tt{}2 {(x}^{2}  - 6x - 7x + 42)

\tt{}2( x \times (x - 6) - 7(x - 6))

\tt{}2(x - 6) \times (x - 7)

5 0
3 years ago
michelle bought the same fabric on 3 different occasions and recorded the data below what was the price per yard of fabric? answ
bazaltina [42]

Please consider the complete question.

Michelle bought the same fabric on 3 different occasions and recorded the data below.

Yards of Fabric         Total Cost

2.2                             $2.53

3.6                             $4.14

4.2                             $4.83

What was the price per yard of fabric?

To find the cost per yard of fabric, we will divide cost of yards by number of yards.

\text{Cost per yard}=\frac{\text{Cost}}{\text{Number of yards}}

\text{Cost per yard}=\frac{\$2.53}{2.2\text{ yards}}

\text{Cost per yard}=\frac{\$1.15}{\text{ yard}}

Let us find cost per yard using 2nd set of data.

\text{Cost per yard}=\frac{\$4.14}{3.6\text{ yards}}

\text{Cost per yard}=\frac{\$1.15}{\text{ yard}}

Similarly we will find cost per yard for 3rd set of data.

\text{Cost per yard}=\frac{\$4.83}{4.2\text{ yards}}

\text{Cost per yard}=\frac{\$1.15}{\text{ yard}}

Therefore, the cost per yard of fabric is $1.15.

4 0
3 years ago
WILL MAKE YOU BRAINLIEST
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Answer: B

negative power= reciprocal

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4 0
4 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

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The area of the triangle above will equal one half of a rectangle that is 5 units long and 3 units wide.
The area of the triangle is 7.5 units and the area of the rectangle is 15 units
5 0
3 years ago
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