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igor_vitrenko [27]
3 years ago
13

Median of 28, 30, 34, 35

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0
You first put them all in order from least to greatest. Now, since 30 and 34 seem to be in the middle, write the number in between them: 30, 31, 32, 33, 34.

And you get your answer as 32. Hope this helped ;)
You might be interested in
I'm confused on how to do this. Please explain step by step. If you respond with just the answer I WILL report you. I would like
Tcecarenko [31]

Answer:

Exact Form:

√2−1

Decimal Form:

0.41421356

…

Step-by-step explanation:

Since  9π/8  is not an angle where the values of the six trigonometric functions are known, try using half-angle identities.

9π/8  is not an exact angle

First, rewrite the angle as the product of  1/2  and an angle where the values of the six trigonometric functions are known. In this case,  9π/8  can be rewritten as

(1/2)*  9π/8 tan ((1/2)*  9π/8)

Use the half-angle identity for tangent to simplify the expression. The formula states that  

tan (0/2)=sin(0)/1+cos(0) sin(9π/4)/1+cos(9π/4)

Simplify

Remove full rotations of  2π  until the angle is between  0  and  2π.

sin(π/4)/1+cos(9π/4)

The exact value of sin(π/4) is √2/2

√2/2/1+cos(9π/4)

Simplify the Denominator

Remove full rotations of  2π  until the angle is between  0  and  2π.√2/2/1+cos(π4)

The exact value of cos(π/4)   is  √2/2.√2/2/1+√2/2

To write  1/1  as a fraction with a common denominator, multiply by  2/2  .√2/2/1/1⋅2/2+√2/2

Write each expression with a common denominator of  2, by multiplying each by an appropriate factor of  1.

Combine.

√2/2/1⋅2/1⋅2+√2/2

Multiply 2 by 1

√2/2/1⋅2/2+√2/2

Combine the numerators over the common denominator.

√2/2/1⋅2+√2/2

Multiply 2 by 1

√2/2/2+√2/2

Multiply the numerator by the reciprocal of the denominator

√2/2  ⋅  2/2+√2

Cancel the common factor of  2  .

Factor out the greatest common factor  2

√2/2⋅1  ⋅  2⋅1/2+√2

Cancel the common factor

√2/2⋅1  ⋅  2⋅1/2+√2

Rewrite the expression.

√2/1  ⋅  1/2+√2

Simplify

Multiply  √2/1  and  1/2+√2

√2/2+√2

Multiply  √2/2+√2  by  2−√2/2−√2

Combine

√2(2−√2)/(2+√2)(2−√2)

Expand the denominator using the FOIL method.

√2(2−√2)/4−2√2+√2⋅2−√2^2

Simplify

√2(2−√2)/2

Apply the distributive property

√2⋅2+√2(−√2)/2

Move  2  to the left of the expression  √2⋅2.

2⋅√2+√2(−√2)/2

Simplify  

√2(−√2)  .

Raise  √2  to the power of  1  .

2⋅√2−(√2^1√2)/2

Raise  √2  to the power of  1  .

2⋅√2−(√2^1√2^1)/2

Use the power rule  a^m  a^n=a^m+n  to combine exponents.

2⋅√2−√2^1+1/2

Add  1  and  1  .

2⋅√2−√2^2/2

Simplify each term.

Multiply  2  by  √2  .

2√2−√2^2/2

Rewrite  √2^2  as  2  .

2√2−1⋅2/2

Multiply  −1  by  2.

2√2−2/2

Reduce the expression by cancelling the common factors.

Factor  2  out of  2√2.

2(√2)−2/2

Factor  2  out of  −2.

2(√2)+2⋅−1/2

Factor  2  out of  

2(√2)+2(−1)2(√2−1)/2

Cancel the common factors.

Factor  2  out of  2  .

2(√2−1)/2(1)

Cancel the common factor.

2(√2−1)/2⋅1

Rewrite the expression.

√2−1/1

Divide  √2−1  by  1  .

√2−1

The result can be shown in multiple forms.

Exact Form:

√2−1

Decimal Form:

0.41421356…

Hope it help. Good luck.

4 0
3 years ago
Pavel, Ruth and Josh have part-time jobs.
MrMuchimi
M+m+z/3=3m
m+m+z=9m
2m+z=9m
z=7m
m+m+7m/3=3m
9m=9m
m=1
1+1+z/3=3
2+z=9
z=7
idk but i think that one person gets paid 7 dollars and the other ppl get paid 1 dollar----- this is probably veryyyyy wrong


8 0
3 years ago
A line includes the points (-3, 8)and (-1, 2). What is its equation in slope- intercept form
Natasha_Volkova [10]
Solve for slope first:
m = \frac{y2 - y1}{x2 - x1}

m = \frac{2-8}{-1-(-3)} = -3

then solve for b in y = mx + b

8 = -3(-3) + b
b = -1

y = -3x - 1
5 0
3 years ago
Make a conjecture about the sum of primes based on the following pattern:
Setler [38]
14= 7+7
16= 8+8
18= 9+9
20= 9+11
22= 10+12
24= 12+12
26= 7+8+11
6 0
3 years ago
Marisa took a survey and discovered that 38 out of 152 students in the seventh grade at her school have more than one pet. What
mamaluj [8]

Answer:

<h3>25%</h3>

Step-by-step explanation:

Total number of student in the school = 152 students

Number of student that have more than one pet = 38

percentage of the students have more than one pet will be expressed as

% of student with more than 1 pet = number of student with more than one pet/total number of student * 100%

% of student with more than 1 pet = 38/152 * 100

% of student with more than 1 pet = 3800/152

% of student with more than 1 pet = 25%

Hence 25% of the students in the school have more than one pet.

3 0
2 years ago
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