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igor_vitrenko [27]
3 years ago
13

Median of 28, 30, 34, 35

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0
You first put them all in order from least to greatest. Now, since 30 and 34 seem to be in the middle, write the number in between them: 30, 31, 32, 33, 34.

And you get your answer as 32. Hope this helped ;)
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According to a Washington Post-ABC News poll, 331 of 502 randomly selected U.S. adults interviewed said they would not be bother
k0ka [10]

Answer:

z=\frac{0.659 -0.5}{\sqrt{\frac{0.5(1-0.5)}{502}}}=7.124  

p_v =P(z>7.124)=5.24x10^{-13}  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is significantly higher than 0.5.  

Step-by-step explanation:

Data given and notation

n=502 represent the random sample taken

X=331 represent the adults that said they would not be bothered if the NAtional security agency

\hat p=\frac{331}{502}=0.659 estimated proportion of people who would not be bothered if the NAtional security agency

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than the majority of 0.5:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.659 -0.5}{\sqrt{\frac{0.5(1-0.5)}{502}}}=7.124  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>7.124)=5.24x10^{-13}  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is significantly higher than 0.5.  

4 0
3 years ago
Hey guys it's been a while can you just help me with these two problems?​
lutik1710 [3]

Answer:

Your already right on both of them lol

Step-by-step explanation:

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BRAINLIEST ANSWER!!
Maksim231197 [3]

Answer:

1. 30(8.75) + 11t = 400

2. 12.5 hours

Step-by-step explanation:

1. What is given is you work for 30 hours per week at a gas station for $8.75 an hour. You also work as a landscaper for $11 an hour. You want to a make a total of $400 per week.

30 hours and $8.75 an hour would be equivalent to 30(8.75)

We don’t know how many hours you work as a landscaper but you earn $11 an hour, which is equivalent to 11t

Finally, you want to earn a total of $400 a week, which means the sum equals 400

30(8.75) + 11t = 400

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400 - 262.5 = 137.5

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Step-by-step explanation:

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