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3 years ago

Median of 28, 30, 34, 35

1 answer:

5 0

You first put them all in order from least to greatest. Now, since 30 and 34 seem to be in the middle, write the number in between them: 30, 31, 32, 33, 34.

And you get your answer as 32. Hope this helped ;)

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if two fractions have the same denominator but different numerators which fraction is greater? Give an example.

krek1111 [17]

The larger fractron will be the fraction with the greater numerator.
ex. 4/5 is greater than 2/5

7 0

3 years ago

Read 2 more answers

A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

2 years ago

2.50c+6a=6344.50 Find each variable

Ksju [112]

Answer:

c=2.4a+2537.8

a=-2.5/6c+1057.4

Step-by-step explanation:

solve for c:

2.50c+6a=6344.50

-6a -6a

2.50c=-6a+6344.50

/2.50 /2.50 /2.50

c=2.4a+2537.8

solve for a:

2.50c+6a=6344.50

-2.5c -2.5c

6a=-2.5c+6344.50

/6 /6 /6

a=-2.5/6c+1057.4

6 0

3 years ago

What is 2(3x + 12y - 5 - 17x - 16y +4) simplified?

fiasKO [112]

Answer:

Step-by-step explanation:

2(3x + 12y - 5 - 17x - 16y +4)

the 2 outside the bracket means we need to multiply everything by 2

6x+24y-10-34x-32y+8

now put all the like-terms together

6x-34x+24y-32y+8-10

now add them together

=-28x-8y-2

now find the HCF

put 2 outside the bracket and then divide every number by 2

2(-14x-4y-1)

this is as simplified it can get

5 0

2 years ago

Which input value produces the same output value for

VashaNatasha [74]

Answer:

-6

Step-by-step explanation:

Took test

7 0

3 years ago