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rosijanka [135]
3 years ago
10

Which of the five measures of center (the mean, the median, the trimmed mean, the weighted mean, and the mode) can be calculated

for quantitative data only?
Mathematics
1 answer:
Sever21 [200]3 years ago
6 0
Quantitative data is information that can be measured, while qualitative data is descriptive data which can not be measured.
All five measures (the mean, the median, the trimmed mean, the weighted mean and the mode) can be calculated for quantitative data only, because they all use values in order to be calculated.
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(10-1) = a(0 - 3)²
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6 0
3 years ago
HELP PLEASE ASAP!!!!
Akimi4 [234]

Answer:

85°

Step-by-step explanation:

add 125+150=275

a circle is 360

so 275+85=360

4 0
2 years ago
Last weekend, Carlos rode his bicycle for 3 hours and traveled 27 miles. On average, at what rate did Carlos travel on his bicyc
mash [69]
Carlos rode an average of 9 miles every hour on his bicycle. It is because 3*9=27 and the distance is rate multiplied by time. use the formula and check it!

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5 0
3 years ago
The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi
inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.        

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

\displaystyle\frac{dr}{dt} = -7\text{ inch per second}

The volume is decreasing at a constant rate.

\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

V = \displaystyle\frac{1}{3}\pi r^2 h

Instant volume =

525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}

Differentiating with respect to t,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)

Putting all the values, we get,

\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

3 0
3 years ago
*30 POINTS* In a group of 53 children, 22 had a dog, 18 had a cat, and 6 had both a dog and a cat. How many children had neither
Gnesinka [82]

Answer:

7

Step-by-step explanation:

Although I don’t see that answer, with 53 children and 22 having a dog, 18 a cat, and 6 with both, you would think to subtract all three of those numbers with 53 to get the remaining with no dogs or cats, which results to 7

6 0
3 years ago
Read 2 more answers
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