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hammer [34]
4 years ago
13

Write the ratio 6 ft to 4yd as a fraction in simplest form.

Mathematics
1 answer:
vesna_86 [32]4 years ago
4 0
First you have to switch yard to feet.  1 yd=3 ft so you have to change 4 to 12.  Then you put the 6 over the 12.  You simplify it to 1/2 so it'll be one half in simplest form.
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The leg lengths of a triangle are 2 millimeters and 2.1 millimeters and the hypotenuse is 2.9 millimeters.Is this a right triang
Nataly_w [17]
Yes

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Download pdf
7 0
4 years ago
Find the common ratio for the following sequence .1, .01, .001
morpeh [17]

Answer:

0.1

Step-by-step explanation:

The <em>common ratio</em> of a sequence is the number you multiply one term to get the next one. Here, we multiply 0.1 by 0.1 to get 0.01, and 0.01 by 0.1 to get 0.001, so our common ratio is 0.1.

5 0
3 years ago
You decide to sell each of your toys for $25. Costs are how much you pay your supplier($11 to make each toy plus a one-time fee
True [87]

Step-by-step explanation:

  |                             |                                     |

2 | ($25 x 2) = $50  |   ($11 x 2 + 18) = $40  |    Profit = $50 - $40 = +$10

  |             ----           |             --------               |                   -------

3 | ($25 x 3) = $75  |  ($11 x 3 = 18) = $51     |    Profit = $75 - $51 = +$24

  |             ----           |            ---------               |                   -------

Total Number of toys = 1+2+3 = 6

Total Earnings = $25+$50+$75 = $150

Total Cost = $29+$40+$51 = $120

Total Profit = $150-$120 = +$30    

5 0
3 years ago
WILL AWARD BRAINLIEST AND 30 PTS IF THERE IS A GOOD EXPLANATION. ANSWER IS NOT 243. question: In how many ways can we put five i
Bumek [7]

Answer:

243 ways

Step-by-step explanation:

Fruits = 5

Bowls = 3

Remember that, There are three bowls for five fruits. So the possible outcomes are:

=> 3^5 = 3*3*3*3*3 = 243 ways

8 0
3 years ago
Two surveys were independently conducted to estimate a population mean, μ. denote the estimates and their standard errors by x1
lyudmila [28]

Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,

V(X)=α2σ2X¯1+β2\sigma2X¯2

Now we want to minimise this subject to α+β=1 or α−β−1=0.

We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise

f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).

We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;

∂f∂α=2ασ2X¯1+λ=0

∂f∂β=2βσ2X¯2+λ=0

∂f∂λ=α+β−1=0

Setting the first two partial derivatives equal we get

α=βσ2X¯2σ2X¯1

Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.

Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd

3 0
3 years ago
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