|sin(x)−sin(y)|=|2sin(x−y2)cos(x+y2)|≤|2sin(x−y2)|
Last on - I think
{0,-9), (-9,0), (-3,-3)}
Answer:
a) $520
b) $580
c) Interest amount is same each year
Step-by-step explanation:
Given - Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withdrawals.
To find - a) How much money was in the account after one year?
b) How much money was in the account after 4 years?
c) Was the amount of money earned in interest the same or different each year?
Proof -
Here given that,
Principal amount = $500
rate of interest = 4% = 4/100 = 0.04
Now,
a)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(1)]
= 500 [ 1 + 0.04] = 520
⇒Amount = $520
b)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(4)]
= 500 [ 1 + 0.16] = 580
⇒Amount = $580
c)
In 2nd year,
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(2)]
= 500 [ 1 + 0.08] = 540
⇒Amount = $540
Now,
Interest in 1st year = 520 - 500 = 20
Interest in 2nd year = 540 - 520 = 20
So,
The interest amount is same each year
If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
