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Stolb23 [73]
3 years ago
12

Find the missing length of the triangle. 26 in. a 24 in.

Mathematics
2 answers:
sleet_krkn [62]3 years ago
7 0
<h3>Answer:  a = 10</h3>

Work Shown:

Apply the pythagorean theorem to get...

a^2 + b^2 = c^2

a^2 + 24^2 = 26^2

a^2 + 576 = 676

a^2 = 676 - 576

a^2 = 100

a = sqrt(100)

a = 10

Elis [28]3 years ago
3 0

Answer:

10

Step-by-step explanation:

26^2-24^2=100

sqrt of 100 is 10

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3. The product of 7/10 and another factor
kicyunya [14]
The correct answer is d 7/7
4 0
3 years ago
Write an equivalent expression to present patricia total earnings this week 7h + 135 + 5h = ?h + ?​
Paul [167]

Answer: 12 h + 135

Step-by-step explanation: 7h +135 + 5h = ?h + ?​

                                             7h +5h +135  

                                            =12h +135

So u combine like terms together  which are 7h and 5h which gives you 12 h.And then you have 135 left,so you add 12h to 135.

Ps.If you don't know what like terms are.I will explain down below.

Like terms are  variable that are the same.For an example 4y and 3y are like terms .Another example is 1/3 xy and 6xy .

Hope this helps :) and if it does please give brainliest .

8 0
2 years ago
(x^2y+e^x)dx-x^2dy=0
klio [65]

It looks like the differential equation is

\left(x^2y + e^x\right) \,\mathrm dx - x^2\,\mathrm dy = 0

Check for exactness:

\dfrac{\partial\left(x^2y+e^x\right)}{\partial y} = x^2 \\\\ \dfrac{\partial\left(-x^2\right)}{\partial x} = -2x

As is, the DE is not exact, so let's try to find an integrating factor <em>µ(x, y)</em> such that

\mu\left(x^2y + e^x\right) \,\mathrm dx - \mu x^2\,\mathrm dy = 0

*is* exact. If this modified DE is exact, then

\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \dfrac{\partial\left(-\mu x^2\right)}{\partial x}

We have

\dfrac{\partial\left(\mu\left(x^2y+e^x\right)\right)}{\partial y} = \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu \\\\ \dfrac{\partial\left(-\mu x^2\right)}{\partial x} = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu \\\\ \implies \left(x^2y+e^x\right)\dfrac{\partial\mu}{\partial y} + x^2\mu = -x^2\dfrac{\partial\mu}{\partial x} - 2x\mu

Notice that if we let <em>µ(x, y)</em> = <em>µ(x)</em> be independent of <em>y</em>, then <em>∂µ/∂y</em> = 0 and we can solve for <em>µ</em> :

x^2\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} - 2x\mu \\\\ (x^2+2x)\mu = -x^2\dfrac{\mathrm d\mu}{\mathrm dx} \\\\ \dfrac{\mathrm d\mu}{\mu} = -\dfrac{x^2+2x}{x^2}\,\mathrm dx \\\\ \dfrac{\mathrm d\mu}{\mu} = \left(-1-\dfrac2x\right)\,\mathrm dx \\\\ \implies \ln|\mu| = -x - 2\ln|x| \\\\ \implies \mu = e^{-x-2\ln|x|} = \dfrac{e^{-x}}{x^2}

The modified DE,

\left(e^{-x}y + \dfrac1{x^2}\right) \,\mathrm dx - e^{-x}\,\mathrm dy = 0

is now exact:

\dfrac{\partial\left(e^{-x}y+\frac1{x^2}\right)}{\partial y} = e^{-x} \\\\ \dfrac{\partial\left(-e^{-x}\right)}{\partial x} = e^{-x}

So we look for a solution of the form <em>F(x, y)</em> = <em>C</em>. This solution is such that

\dfrac{\partial F}{\partial x} = e^{-x}y + \dfrac1{x^2} \\\\ \dfrac{\partial F}{\partial y} = e^{-x}

Integrate both sides of the first condition with respect to <em>x</em> :

F(x,y) = -e^{-x}y - \dfrac1x + g(y)

Differentiate both sides of this with respect to <em>y</em> :

\dfrac{\partial F}{\partial y} = -e^{-x}+\dfrac{\mathrm dg}{\mathrm dy} = e^{-x} \\\\ \implies \dfrac{\mathrm dg}{\mathrm dy} = 0 \implies g(y) = C

Then the general solution to the DE is

F(x,y) = \boxed{-e^{-x}y-\dfrac1x = C}

5 0
3 years ago
Please help with question 2, I’m too tired to think right now, and it’s for my little sister and it’s due tomorrow! Ignore the n
marishachu [46]

Answer:

2000 L

Step-by-step explanation:

There are 1250 L of water in a tank at present. If the tank is 0.625 full, what is the capacity of the tank?

The simple solution is:

1250 L ÷ 0.625 = 2000 L

The algebraic solution is:

Let <em>c</em> equal the capacity of the tank.

Therefore, <em>c</em> × 0.625 = 1250.

Divide both sides by 0.625:

<em>c</em> × 0.625 ÷ 0.625 = 1250 ÷ 0.625

And simplify:

<em>c</em> = 1250 ÷ 0.625

<em>c</em> = 2000

5 0
3 years ago
The distributive property to factor out the greatest common<br> 24; - 16 =<br><br> Please help...
Naddik [55]

Answer:

8

Step-by-step explanation:

5 0
3 years ago
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