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Arada [10]
2 years ago
12

Y = 2x + 3 y = 1/2 x – 3 y = –2x – 3 y = 1/2 x + 3

Mathematics
1 answer:
vodka [1.7K]2 years ago
5 0

Answer:

y = 1/2 x + 3

Step-by-step explanation:

the positive 3 is the y intercept and the positive 1/2 is rise over run up-1 & 2 to the right

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Jill is considering a 7/23 balloon mortgage with an interest rate of 3.5% to
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Answer: A. $1189.97

Step-by-step explanation:

8 0
2 years ago
Help me please I need
vagabundo [1.1K]

Answer:

I think the answer is A=49

8 0
3 years ago
Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
3 years ago
Find the solution to the equation or inequality below. You must type in the entire solution, for example x=5 if it is an equatio
Alina [70]
5x - 9 = 26
5x - 9 + 9 = 26 + 9
5x = 35
5x/5 = 35/5
X = 7
4 0
3 years ago
Your new phew is standing on his deck which is 4 feet off the ground. He tosses his toy up into the air. The equation h(t) = -2t
Tpy6a [65]

Answer:

The height of the toy is 9 feet after 1 second

Step-by-step explanation:

we have

h(t)=-2t^2+7t+4

where

h(t) is the toys height from the ground

t is the time in seconds

so

For t=1 sec

substitute the value of t in the quadratic equation and solve for h(t)

h(1)=-2(1)^2+7(1)+4

h(1)=9\ ft

3 0
3 years ago
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