The range is 77. you calculate range by subtracting the smallest number from the biggest number.
Let r = radius of the hard rubber ball.
The circumference of the ball is 13 inches, therefore
2πr = 13
r = 13/(2π) = 2.069 inches
The diameter of the ball is 2*2.069 = 4.138 inches.
The ball is hard and cannot be compressed. Therefore the length of a side of the smallest cube-shaped box with integer dimensions is 5 inches.
The volume of the box is 5³ = 125 in³.
Answer: 125 in³
Answer:
The solution is similar to the 2-point form of the equation for a line:
y = (y2 -y1)/(x2 -x1)·x + (y1) -(x1)(y2 -y1)/(x2 -x1)
Step-by-step explanation:
Using the two points, write two equations in the unknowns of the equation of the line.
For example, you can use the equation ...
y = mx + b
Then for the points (x1, y1) and (x2, y2) you have two equations in m and b:
b + (x1)m = (y1)
b + (x2)m = (y2)
The corresponding augmented matrix for this system is ...
![\left[\begin{array}{cc|c}1&x1&y1\\1&x2&y2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Cc%7D1%26x1%26y1%5C%5C1%26x2%26y2%5Cend%7Barray%7D%5Cright%5D)
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The "b" variable can be eliminated by subtracting the first equation from the second. This puts a 0 in row 2 column 1 of the matrix, per <em>Gaussian Elimination</em>.
0 + (x2 -x1)m = (y2 -y1)
Dividing by the value in row 2 column 2 gives you the value of m:
m = (y2 -y1)/(x2 -x1)
This value can be substituted into either equation to find the value of b.
b = (y1) -(x1)(y2 -y1)/(x2 -x1) . . . . . substituting for m in the first equation
Score on fourth test should be 95
68 + 79 + 98 + 95 = 340
340 divide by 4 (as there are 4 tests) = 85
The slope is -5/0. Hope this helps