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Basile [38]
3 years ago
13

A ball is thrown into the air with an upward velocity of 32 ft/s. Its height h in feet after t seconds is given by the function

mc015-1.jpg. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. What is the ball’s maximum height? 2 s; 22 ft 1 s; 22 ft 2 s; 6 ft 1 s; 54 ft
Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0
<span>2 s; 22 ft 1 s; 22 ft 2 s; 6 ft 1 s; 54 ft i et itdont g</span>
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The range is 77. you calculate range by subtracting the smallest number from the biggest number.
5 0
2 years ago
Sophie has a hard rubber ball whose circumference measures 13 inches. she wants to store it in a box. what is the number of cubi
Alexus [3.1K]
Let r =  radius of the hard rubber ball.
The circumference of the ball is 13 inches, therefore
2πr = 13
r = 13/(2π) = 2.069 inches
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The ball is hard and cannot be compressed. Therefore the length of a side of the smallest cube-shaped box with integer dimensions is 5 inches.
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5 0
3 years ago
How do you find the equation of a line with Guassian elimination given two points?
Paraphin [41]

Answer:

  The solution is similar to the 2-point form of the equation for a line:

  y = (y2 -y1)/(x2 -x1)·x + (y1) -(x1)(y2 -y1)/(x2 -x1)

Step-by-step explanation:

Using the two points, write two equations in the unknowns of the equation of the line.

For example, you can use the equation ...

  y = mx + b

Then for the points (x1, y1) and (x2, y2) you have two equations in m and b:

  b + (x1)m = (y1)

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The corresponding augmented matrix for this system is ...

  \left[\begin{array}{cc|c}1&x1&y1\\1&x2&y2\end{array}\right]

____

The "b" variable can be eliminated by subtracting the first equation from the second. This puts a 0 in row 2 column 1 of the matrix, per <em>Gaussian Elimination</em>.

  0 + (x2 -x1)m = (y2 -y1)

Dividing by the value in row 2 column 2 gives you the value of m:

  m = (y2 -y1)/(x2 -x1)

This value can be substituted into either equation to find the value of b.

  b = (y1) -(x1)(y2 -y1)/(x2 -x1) . . . . . substituting for m in the first equation

7 0
3 years ago
A student scored 68, 79, and 98 on three algebra tests. what must he score on the fourth test in order to have an average grade
slega [8]
Score on fourth test should be 95

68 + 79 + 98 + 95 = 340

340 divide by 4 (as there are 4 tests) = 85
7 0
3 years ago
Will give brainliest if correct.
Allisa [31]
The slope is -5/0. Hope this helps
8 0
2 years ago
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