X²+20=0
x=±√(-80)/2
x=±4i√5/2=2i√5
factorised it is then
(x+2i√5)*(x-2i√5)
Answer:
if the area is 7 then the total side length is sqrt 7. 2 is also sqrt 4 so x pretty much equals sqrt 3. this equation is a typo, as sqrt isn't a solution. moreover if you factor the square, it will equal x squared plus 4x plus 4.
Answer:
c) third quadrant
Step-by-step explanation:
Answer:
Answer is B: (-sqrt(3/2 , -1/2)
Step-by-step explanation:
First convert radians to degrees
theta = (7pi/6)*(180/pi)
=210 degrees
Cos(210 degrees)= -sqrt3/2
Thats the x coordinate
sin(210 degrees)= -1/2
thats the y coordinate
Answer:
3. Intersect at exactly one point. ( (2/3), (-2/3) )
Step-by-step explanation:
To make the comparison of these lines easier, let's rewrite the 2nd equation into slope-intercept form, as the 1st equation is in slope-intercept form.
[1] y = 2x - 2
---------------------
[2] 6x + 3y = 2 ==> 3y = 2 - 6x ==> y = -2x + (2/3)
[2] y = -2x + (2/3)
So now that we have both equations in slope-intercept form, we can see that the two equations are both linear, have different slopes, and have different y-intercepts.
Since these equations have both different slopes and different y-intercepts, we know that the lines will cross at least one point. We can confirm that the lines only cross at a single point using the fact that both equations are linear, meaning there will only be one point of crossing. To find that point, we can simply set the equations equal to each other.
y = 2x - 2
y = -2x + (2/3)
2x - 2 = -2x + (2/3)
4x = (8/3)
x = (8/12) = (2/3)
And plug this x value back into one of the equations:
y = 2x - 2
y = 2(2/3) - 2
y = (4/3) - (6/3)
y = (-2/3)
Thus these lines only cross at the point ( (2/3), (-2/3) ).
Cheers.
