3 years ago

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Mathematics

1 answer:

Julli [10]3 years ago

7 0

Answer:

the answer is 3 !

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gayaneshka [121]

Answer:

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Step-by-step explanation:

We are given that

$\frac{dV}{dt}=15ft^3/min$

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Let d be the diameter of pile

Height of pile=h

d=h

Radius of pile,r= $\frac{d}{2}=\frac{h}{2}$

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Substitute the values

$15=\frac{1}{4}\pi(12)^2\frac{dh}{dt}$

$\frac{dh}{dt}=\frac{15\times 4}{\pi(12)^2}$

$\frac{dh}{dt}=0.13ft/min$

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4 years ago

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