Answer:
Mass of the resulting strontium fluoride precipitate = 34.51 g
Step-by-step explanation:
First, write a correctly balanced equation for the reaction taking place:
Sr(NO3)2(aq) + 2NaF(aq) ===> SrF2(s) + 2NaNO3(aq)
Next, Find the limiting reactant:
moles Sr(NO3)2 present = 0.150 L x 2.671 mol/L = 0.40065 moles
moles NaF = 0.210 L x 2.617 mol/L = 0.54957 moles
LIMITING REACTANT = NaF
because you need twice the moles of NaF as you have Sr(NO3)2 (see bal. eq.)
Mass SrF2 producedb =
0.54957 mol NaF x 1 mol SrF2 / 2 mol NaF x 125.6 g/mol = 34.51 g SrF2 produced
Hi !
Answer : -1.8<em>Difficult to explain here, so I put a graph as explanation and prove.</em>
A(n)= 250 + (n)(0.03*250); $355
I can also explain this in depth in the comments if you wish.
Answer:
c
Step-by-step explanation:
1 + tan²theta = sec²theta
tan²theta = 3² - 1
tan²theta = 8
tan theta = sqrt(8)
Positive because Quadrant 1
sqrt(8) = sqrt(4×2) = sqrt(4)×sqrt(2)
= 2×sqrt(2)
Answer: 46ft
Step-by-step explanation:
You take the area and find it's square root then multiply it by how many sides there are to the figure in this case it is 4 sides so you multiply it by 4 getting 46