In bmultiplying, you always have to move the decimal of the product the amount of place values the decimal has in each factor, for example, 1.50 times 1.50= 2.25, the factors together have 4 decimals, so you move the decimal 4 times to the right (try it, it gets rid of alot of zeros in the answer.)
43.54 divided by 3.5= unit rate
12.44
Answer:
Option A - The distance Train A traveled in 1 h is equal to the distance Train B traveled in 1 h.
Step-by-step explanation:
Given : The distance Train A traveled is modeled by the function 
where d represents distance in miles and t represents time in hours.
To find : How does the distance Train A traveled in 1 hour compare to the distance Train B traveled in 1 hour?
Solution :
Distance traveled by Train A in 1 hour is


Distance traveled by Train B in 1 hour is


or for B, we have 324 miles in 4 hours. If that is at a constant speed, it travels 324/4 = 81 miles in one hour
Therefore, The distance Train A traveled in 1 h is equal to the distance Train B traveled in 1 h.
Hence, Option A is correct.
Answer:
28.27 cm/s
Step-by-step explanation:
Though Process:
- The punch glass (call it bowl to have a shape in mind) is in the shape of a hemisphere
- the radius
- Punch is being poured into the bowl
- The height at which the punch is increasing in the bowl is

- the exposed area is a circle, (since the bowl is a hemisphere)
- the radius of this circle can be written as

- what is being asked is the rate of change of the exposed area when the height
- the rate of change of exposed area can be written as
. - since the exposed area is changing with respect to the height of punch. We can use the chain rule:

- and since
the chain rule above can simplified to
-- we can call this Eq(1)
Solution:
the area of the exposed circle is

the rate of change of this area can be, (using chain rule)
we can call this Eq(2)
what we are really concerned about is how
changes as the punch is being poured into the bowl i.e 
So we need another formula: Using the property of hemispheres and pythagoras theorem, we can use:

and rearrage the formula so that a is the subject:

now we can derivate a with respect to h to get 

simplify

we can put this in Eq(1) in place of 
and since we know 

and now we use substitute this
. in Eq(2)

simplify,

This is the rate of change of area, this is being asked in the quesiton!
Finally, we can put our known values:

from the question


As a percentage it would be 63.5% and as a fraction it would be 635/ 1000 or 127/200