Question

"absmiddle" class="latex-formula">and
${g}^{ - 1}(x) = \frac{x + 6}{3}$. With g(x) and
${g}^{ - 1}(x)$, find
${g}^{ - 1}(g(10))$. Make sure to show your work.​

Answer 1

Hey there! :)

Answer:

$g^{-1} (g(10))=10$

Step-by-step explanation:

Begin by calculating g(10):

g(x) = 3x - 6

Substitute in 10 for x:

g(10) = 3(10) - 6

g(10) = 30-6

g(10) = 24.

Plug '24' into 'x' into $g^{-1} (x)$

$g^{-1} (24)=\frac{(24) + 6}{3}$

Simplify:

$g^{-1} (24)=\frac{30}{3}$

$g^{-1} (24)=10$