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kobusy [5.1K]
3 years ago
15

Find the interest is you invest $3500 for 9 years at a rate of 4.5%

Mathematics
1 answer:
dybincka [34]3 years ago
5 0
Aproxx. 90 or 89 it was to long to type so im giving you the estiment
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What is the value of x in the equation 0.3x + 1.7 = 2?
Softa [21]

Answer:

x = 1

Step-by-step explanation:

0.3x+1.7=2\\\\0.3x+1.7-1.7=2-1.7\\\\0.3x=0.3\\\\\frac{0.3x=0.3}{0.3}\\\\\boxed{x=1}

Hope this helps.

6 0
3 years ago
Determine the margin of error for a 90% confidence interval to estimate the population mean when s = 40 for the sample sizes bel
Ann [662]

Answer:

a) The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is 10.02.

Step-by-step explanation:

The t-distribution is used to solve this question:

a) n = 14

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 14 - 1 = 13

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 13 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.7709

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.7709\frac{40}{\sqrt{14}} = 18.93

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for a 90% confidence interval when n = 14 is 18.93.

b) n = 28

27 df, T = 1.7033

M = T\frac{s}{\sqrt{n}} = 1.7033\frac{40}{\sqrt{28}} = 12.88

The margin of error for a 90% confidence interval when n=28 is 12.88.

c) The margin of error for a 90% confidence interval when n = 45 is

44 df, T = 1.6802

M = T\frac{s}{\sqrt{n}} = 1.6802\frac{40}{\sqrt{45}} = 10.02

The margin of error for a 90% confidence interval when n = 45 is 10.02.

3 0
3 years ago
In the equation 9x2 - 4 = (px - t)(px + t), p and t are constants. What is the value of p + t?
Alexxx [7]

Answer: 2

Step-by-step explanation:

4 0
2 years ago
What is another way to write 42 + 63
satela [25.4K]
You could write this  by going 63+42 or add 63 and 42 
hope that's what you are looking for ;-)<span />
7 0
3 years ago
Read 2 more answers
What is the maximum number of possible extreme values for the function,<br> f(x) = х2 -7x – 6?
timama [110]

Answer:

Only one extreme value of f(x) is possible.

Step-by-step explanation:

We are given the quadratic function of independent variable x which is f(x) = x² - 7x - 6 ......(1)

Now. the condition for extreme values of f(x) is \frac{df(x)}{dx} =0

Hence, differentiating both sides of equation (1) with respect to x, we get

\frac{df(x)}{dx} = 2x -7 = 0

⇒ x = 3.5.

So there is only one value of x for which f(x) has extreme value which is x = 3.5.

Therefore, only one extreme value of the given function is possible. (Answer)

3 0
3 years ago
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