(WILL MARK BRAINILEST) Consider the two functions shown here. Which function grows faster for large positive values of x? [Note:
Function 1 is shown in the graph.]
A) Function 1, because it has larger x values than function 2.
B) Function 1, because the y-value for x = 1 is greater in function 1.
C) Function 2, because all the range values of the function are positive.
D) Function 2, because the y-values increase faster than the y-values in function 1.
A) Function 1, because it has larger x values than function 2.
B) Function 1, because the y-value for x = 1 is greater in function 1.
C) Function 2, because all the range values of the function are positive.
D) Function 2, because the y-values increase faster than the y-values in function 1.
2 answers:
D) Function 2, because the y-values increase faster than the y-values in function 1.
Step-by-step explanation:
The graph of function 1 is that of a linear function.
Finding the slope of the line,
Taking points (0,5) and (1,9) on the graph
m₁=rise/run
rise=Δy = 9-5 =4
run =Δx =1-0 =1
m₁ = 4/1 =4
This function increase at a constant rate
In the second function containing the table, plot the table values to see the behavior of the function. It is noticed that the slope in increasing . This means the function grows faster for large positive values of x as attached;
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Keywords : functions, grows, faster, large, positive ,graph
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<h2>Answer:</h2>
0 - 17i
<h2>Step-by-step explanation:</h2>Given expression;
i⁸⁰ + i³⁸ - i17
To express the expression in the form a+bi;
<em>i. Rewrite the expression such that it contains terms in i²</em>
(i²)⁴⁰ + (i²)¹⁹ - i17
<em>ii. Solve the result from (i) above using the identity i² = -1</em>
We know that the square root of -1 is i. i.e
<em>Squaring both sides gives</em>
<em>=> </em><em />
=> -1 = i²
Therefore,
i² = -1
<em>Substitute i² = -1 in step (i) above</em>
(-1)⁴⁰ + (-1)¹⁹ - i17
<em>(iii) Solve the result in (ii)</em>
We know that the when a negative number is raised to the power of an even number, the result is a positive number. If it is raised to the power of an odd number, the result is a negative number. Therefore,
(-1)⁴⁰ + (-1)¹⁹ - i17 becomes
1 + (-1) - i17
0 - i17
<em>(iv) Write the result from (iii) in the form a+bi</em>
0 - 17i