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elena-s [515]
3 years ago
14

Suppose that a server sends four packets of audio data, in 15 seconds each. The first is sent by the server exactly at noon (12:

00:00), while each of the three successive packets is sent immediately after the completion of its predecessor. The client, on the other hand, receives the four packets beginning at 12:00:03, 12:00:20, 12:00:41, 12:00:59 respectively. What is the smallest delayed wait time (buffer) in seconds that would ensure the client had seamless playback (i.e. each packet plays immediately after the previous one ends)?
Computers and Technology
1 answer:
Romashka [77]3 years ago
3 0

Answer:

15

Explanation:

for seamless playback each packet should be played before their predecessor so

4th packet will start at 12:01:03

3rd packet will start at 12:00:48

2nd packet will start at 12:00:33

1st packet will start at 12:00:18

as first packet arrives at 12:00:03 so wait time is 15 seconds for seamless playback

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