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madreJ [45]
3 years ago
12

Solve the linear question

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0
m + 4 = -7 + 2m


Subtract m from both sides.
4 = -7 + m

Add 7 to both sides.
11 = m

Therefore, m = 11.
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The roosevelt middle school band is having a fundraiser. They sold a total of 300 hotdogs and hamburgers. Hot dogs were sold for
STALIN [3.7K]

Answer:

180 hamburgers

120 hotdogs

Step-by-step explanation:

In this question, we are asked to calculate the number of hamburgers and hotdogs sold by a company given the amount made by them and the total number of these snacks sold

We proceed as follows;

Let the amount of hotdogs sold be x and the amount of hamburgers sold be y.

We have a total of 300 snacks sold, mathematically;

x + y = 300 ..........(I)

Now let’s look at the prices.

x number of hotdogs sold at $2, this give a total of $2x hotdogs

y number of hamburgers sold at $3, this give a total of $3y.

Adding both to give total, we have ;

2x + 3y = 780.......(ii)

This means we have two equations to solve simultaneously. From equation 1, we can say x = 300 -y

Now let’s insert this in the second equation;

2(300-y) + 3y = 780

600-2y + 3y = 780

y = 780-600 = 180

Recall; x + y = 300

x = 300 -y

x = 300-180 = 120

5 0
3 years ago
Read 2 more answers
A small pebble has a mass of<br> about<br> 20 L<br> b.<br> 20 ml<br> 20 g<br> 20 kg<br> d.
zhuklara [117]

Answer:

20g

since mass should be in kg or gram if small then g

7 0
3 years ago
Which statement is true about polynomial 5s^6t^2 + 6st^9 - 8s^6t^2 - 6t^7 after it has been fully simplified?
Marina86 [1]

Answer:  3t²(2st⁷ - s⁶ - 2t⁵)

<u>Step-by-step explanation:</u>

5s⁶t² + 6st⁹ - 8s⁶t² - 6t⁷     <em>5s⁶t² and - 8s⁶t² are like terms which = -3s⁶t² when combined</em>

=          6st⁹ - 3s⁶t² - 6t⁷      <em>next, factor out the GCF of 3t²</em>

=      3t²(2st⁷ - s⁶ - 2t⁵)

5 0
3 years ago
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Let F be a field, and suppose a EF, a *0. Prove that a has a unique multiplicative inverse.
bezimeni [28]

Answer with Step-by-step explanation:

Let F be a field .Suppose a\in F and a\neq 0

We have to prove that a has unique multiplicative inverse.

Suppose a has two inverses b and c

Then, ac=1,ab=1 where 1 =Multiplicative identity

ac=ab

c=b (cancel a on both sides)

Hence, a has unique multiplicative inverse.

6 0
3 years ago
MAAATTTHH HELP PLEEASSEE WILL GIVE 5 STARS FOR CORRECT ANSWERS
Cloud [144]
I know you don't wanna do the work or don't know how but just get the m a t h w a y a-p-p and type the equations in and it'll tell you what x is
4 0
3 years ago
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