3 years ago

When constructing an angle bisector, why do the arcs intersect?

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

3 0

<span>There must be an intersection of the arcs so you can connect the vertex of the angle to it</span>

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zmey [24]

Answer:

$u^2-u-6=0$

where

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Step-by-step explanation:

we have

$(x-4)^2-(x-4)-6=0$

Let

$u=(x-4)$

substitute in the expression above

$(u)^2-(u)-6=0$

Solve for u

Complete the square

$(u^2-u+0.25)=6+0.25$

$(u^2-u+0.25)=6.25$

Rewrite as perfect squares

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square root booth sides

$u-0.5=\pm2.5$

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Remember that

$u=(x-4)$

For u=3

$3=(x-4)$ ----> $x=7$

For u=-2

$-2=(x-4)$ ----> $x=2$

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-----

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