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fenix001 [56]
2 years ago
6

69 POINTS AND BRAINLIEST Part A: List two pieces of information that are provided by the graph and one piece of information that

is not provided by the graph. (4 points)
Part B: Calculate the interquartile range of the data, and explain in a sentence or two what it represents. (4 points)

Part C: Explain what affect, if any, there will be if an outlier is present. (2 points)

Mathematics
1 answer:
Schach [20]2 years ago
6 0

Answer:

Part A: The info in the graph represents a box & whisker plot

Part B: its 25 and it represents the gray area in the plot

Part C: the outlier is bigger

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Help me with ma work pls
Serga [27]
Simply you would do

45+10 time the number of days

So

45+10 x 2 and then you would put the answer in the next Collin
5 0
2 years ago
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Evaluate using <br> Definite integrals
swat32

Since [0,4]=[0,1]\cup(1,4], we can rewrite the integral as

\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt

Both integrals are quite immediate: you only need to use the power rule

\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}

to get

\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4

Now we only need to evaluate the antiderivatives:

\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15

So, the final answer is 15.

4 0
3 years ago
3/4 (x-12)=12<br> And 3/4y-12=12
lianna [129]
3/4 (x-12)=12
3/4x - 9= 12
        +9    +9
3/4x=21
*3/4     *3/4
x= 15 3/4

and 

3/4y-12=12
       +12  +12
3/4y = 24
*3/4    *3/4
y= 18
5 0
3 years ago
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A shipping container will be used to transport several 140-kilogram crates across the
velikii [3]

Answer:

91.42 crates

Step-by-step explanation:

Let

Greatest Number of 140kg crates = x

weight of crate = 140-kilogram

Weight of other shipment = 13200 kilograms

greatest weight of container = 26000 kilograms

Weight of other shipment + (weight of crate * number of crates) ≤ greatest weight of container

13,200 + 140x ≤ 26,000

140x ≤ 26,000 - 13,200

140x ≤ 12,800

x ≤ 12,800/140

x ≤ 91.42 kilograms

Greatest Number of 140kg crates = 91.42 crates

8 0
3 years ago
HELP ME PLEASE THANK YOU
kolbaska11 [484]
It would be the seconf answer

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