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Kaylis [27]
3 years ago
15

Subtract j from 9, then subtract 3 from the result

Mathematics
2 answers:
vladimir2022 [97]3 years ago
8 0

Answer:

j-12

Step-by-step explanation:

without knowing what j is all you can do is combine like terms like -3 and -9

Temka [501]3 years ago
4 0

Answer

(9-j)-3

Step-by-step explanation:

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The sum of four consecutive even integers is 256. what are the numbers?
Naily [24]

Answer:

61 , 63 , 65 , 67

Step-by-step explanation:

Let the least even number be denoted by x. The sum of the four consecutive even numbers would be:

(x) + (x + 2) + (x + 4) (x + 6) = 256

First, simplify. Combine all like terms:

x + x + x + x + 2 + 4 + 6 = 256

4x + 12 = 256

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 12 from both sides of the equation:

4x + 12 (-12) = 256 (-12)

4x = 256 - 12

4x = 144

Next, divide 4 from both sides of the equation:

(4x)/4 = (144)/4

x = 144/4

x = 61

61 is your first number. Find the next 3 consecutive numbers:

x = 61

x + 2 = 63

x + 4 = 65

x + 6 = 67

Check:

61 + 63 + 65 + 67 = 256

256 = 256

~

7 0
2 years ago
1. Find each measure.<br> a)<br> m20<br> 8<br> R<br> Select<br> 110"<br> S<br> 8<br> T<br> c)
Zepler [3.9K]

Answer:

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7 0
2 years ago
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What is the square root of 81
Kay [80]
The square root of 81 is 9
Your answer is <em>9
</em>
Work:
9 x 9 = 81
7 0
2 years ago
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Help for median Xoxo
Tasya [4]
9.8 is the middle number which is the median
5 0
3 years ago
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The frequency of the musical note C4 is about 261.63 Hz. What is the frequency of the note a perfect fifth below C4?
kolbaska11 [484]

Answer:

The frequency of the note a perfect fifth below C4 is;

B- 174.42 Hz

Step-by-step explanation:

Here we note that to get the "perfect fifth" of a musical note  we have to play a not that is either 1.5 above or 1.5 below the note to which we reference. Therefore to get the frequency of the note a perfect fifth below C4 which is about 261.63 Hz, we have

1.5 × Frequency of note Y = Frequency of C4

1.5 × Y = 261.63

Therefore, Y = 261.63/1.5 = 174.42 Hz.

6 0
2 years ago
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