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Liula [17]
2 years ago
9

HELP IM LOW KEY FIGHTING WITH MY MUM ABOUT THIS

Mathematics
2 answers:
HACTEHA [7]2 years ago
8 0

Answer:

51.111, 17, 81, 15

Step-by-step explanation:

Fed [463]2 years ago
5 0
1. 2300 divided by 45= 51
2.357 divided by 21= 17
3. 1215 divided by 15= 81
4.360 divided by 24= 15
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Solve the equation and check the solution. 14-2n=-32
makvit [3.9K]

14 - 2n = -32

32 + 14 = 2n

46 = 2n

46/2 = n

23 = n


Checking:

14 - 2(23) = -32

14 - 46 = -32

-32 = -32 (Matched, answer is correct n = 23)

4 0
3 years ago
Find the coordinates of the vertices of the image of triangle ijk after it is dilated by a scale factor of two using the organ a
ycow [4]
What are the answer choices?
8 0
3 years ago
9•(-5)<br><br> A. -45<br> B. -95<br> C. 4<br> D. 45
alexgriva [62]

Answer:

A. -45

Step-by-step explanation:

multiplying a positive an a negative number gives out a negative result

so when we multiple 9 with -5 the result is -45

3 0
3 years ago
Read 2 more answers
If you walk 100 m forward And 35 m backwards towards your starting point would what is the distance and displacement explain you
Rzqust [24]

Answer:

imater?

Step-by-step explanation:

4 0
3 years ago
A quadratic equation is shown below:
sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

3x^{2}-11x+10=0 has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

\frac{d}{dx}(3x^{2}-11x+10)=6x-11

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}

6 0
3 years ago
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