Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Answer:
6x^2-8x-64
Step-by-step explanation:
the answer for solving a quadrilateral
is base times height
so the base is 2x-8 and the height is 3x+8
(2x-8)(3x+8)
expand
6x^2-8x-64
Hope that helps :)
Please give brainliest
Answer:
a) alternate interior angles theorem
b) OXP ≅ XOL
c) XO ≅ OX
d) reflexive property (i'm not sure about this one)
e) ΔXOP ≅ ΔOXL
f) cpctc
make sure to double check the fourth one