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Ivan
3 years ago
5

What is the value of the expression Alco

Mathematics
1 answer:
Marysya12 [62]3 years ago
4 0

Answer:What is the value of the expression

What is the value of the expression

Alco

What is the value of the expression

Alco

Step-by-step explanation:What is the value of the expression

Alco

What is the value of the expression

What is the value of the expression

Alco

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Which equation represents the relationship between x and y shown in the table ?
charle [14.2K]
The very first one (the very left one)
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The area of a square quilt is 196 square inches. There is a smaller square patch on the quilt with an area of 49 square inches.
Makovka662 [10]




To find your answer you would find the perimeter of the small square which is 28.

You would then find the perimeter of the big square which is 56. 

Next, you subtract 56 from 28 and get 28.  

So the difference is 28 inches.

Hope this helps!!



5 0
3 years ago
Read 2 more answers
What the answer? 8x-(2x-3)=12
nevsk [136]

Answer:

x= 3/2 or 1.5

Step-by-step explanation:

First of all, you can take out the parenthesis because 8x is subtracting 2x-3.

8x-2x-3=12

6x-3=12

  +3  +3

6x= 15

6x/6= 15/6

x= 3/2 or 1.5

Hope this helps!

8 0
3 years ago
Which equation represents a line which is parallel to the line y = -6x – 1?
icang [17]

Answer:

6x+y=-8 because it will be y=-6x-8 having same slope with the line given

4 0
3 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
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