Answer:
50x^4 +25x^3 +103x^2 +25x +49
What equations are there?
Answer:
Step 4
part a: no answer yet still having trouble showing my work
part b:
-0.125(x-24)^2+50
-0.125(x-24)(x-24)+50
-0.125(x^2-24x-24x+576)+50
-0.125(x^2-48x+576)+50
-0.125x^2+6x-75+50
-0.125x^2+6x-22
a=-0.125
b=6
c=-22
part c: yes he went through
part d:
plug in roots (4,0) and (44,0)
if x is 4 and y is 0
0=-0.125(4)^2+6(4)-22
0=-2+24-22
0=-2+2
0=0
if x=44 and y=0
0=-0.125(44)^2+6(44)-22
0=-242+264-22
0=-242+242
0=0
Answer:
The base is 10 meters
Step-by-step explanation:
The area of a right triangle is (b × h) ÷ 2 = a
Let's input the given values and find the value of b:
(b × 4) ÷ 2 = 20
4b ÷ 2 = 20
2b = 20
b = 10
Check:
(10 × 4) ÷ 2 = 20
40 ÷ 2 = 20
20 = 20
It works!
it would be positive because the positive number is bigger than the negative number.
