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allsm [11]
4 years ago
14

applied vs. actual manufacturing overhead davis manufacturing corporation applies manufacturing overhead on the basis of 150% of

direct labor cost. an analysis of the related accounts and job order cost sheet indicates that during the year total manufacturing overhead incurred was $472,500 and that at year-end work in process inventory, finished goods inventory, and cost of goods sold included $60,000, $30,000, and $210,000, respectively, of direct labor incurred during the current year. a. determine the under applied manufacturing overhead at year-end (assume it is significant).
Business
1 answer:
Mashcka [7]4 years ago
8 0

Answer:

Subapplication of    22,500

journal entry:

WIP                   4,500 debit

finished goods 2,250 debit

COGS               15,750 debit

    factory overhead               22,500 credit

Explanation:

Direct Labor cost during the year:

60,000 + 30,000 + 210,000 = 300,000 direct labor

<u></u>

<u>Applied overhead:</u>

cost driver x predetermined rate

300,000 x 150% = 450,000

Actual overhead:   472,500

Subapplication of    22,500

as this is a significant amount we must adjust the WIP  inventory, cost of goods sold and fnished goods inventory

to know the adjustment on each account we calcualte each account percentage:

300,000   -->   22,500

60,000 --> 60,000/300,000 x 22,500 = 4,500 endingWIP

30,000 --> 30,000/300,000 x 22,500  = 2,250 finished goods

210,000--> 210,000/300,000 x 22,500 = 15,750 COGS

we do the adjuting entry to increase overhead and transfer into each concept

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Answer:

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How does a business achieve economies of scale?
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Assume a​ Cobb-Douglas production function of the​ form: q equals 10 Upper L Superscript 0.33 Baseline Upper K Superscript 0.75.
Gnesinka [82]

Answer:

Since 0.33 + 0.75 = 1.08 is greater than one, this production function therefore exhibits increasing returns to scale.

Explanation:

From the question, we have the following restated equation:

q=10L^{0.33} K^{0.75}

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To determine the types of returns to scale, we increase each of L and K inputs by constant amount c as follows:

q = 10(cL)^{0.33}(cK)^{0.75}

We can now solve as follows;

q = 10c^{0.33+0.75} L^{0.33}K^{0.75}

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A) Part-time members must sever employment relationships with former employers

D) IASB shall comprise 16 members, and up to 3 of those members may be part-time

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Answer:

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