The solution to the simultaneous equation is x = 1 and y = 3
<h3>How to solve simultaneous equation?</h3>
1 / 3 x + y = 10 / 3
2x + 1 / 4 y = 11 / 4
multiply equation one by 3 and multiply equation 2 by 4
Therefore,
x + 3y = 10
8x + y = 11
hence,
x + 3y = 10
24x + 3y = 33
23x = 23
x = 23 / 23
x = 1
Therefore,
1 + 3y = 10
3y = 10 - 1
3y = 9
y = 9 / 3
y = 3
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8, because you’re doubling the numbers so 3x2=6 and 4x2=8.
Radius of circle would be R=a×✓2/2=√2 and Circle area is then A=R^2π=✓2^2π=2π or 2×3.14=6.28...
The median average refers to number in the middle of the set. But we need to write it in chronological order.
Now the set becomes 57, 60, 62, 65.
Now find the number in the middle. In this case, it both 60 and 62.
But we need one number.
So, we will take the average of both of them.
60 + 62 = 122
122 / 2 = 61
So, 61 is the median of the set.
EDIT:
Big thanks to mkersten for finding two errors in my answer!
Wouldnt u add all those amounts of money then divide it by 40 so it would give u the amount of money needed to cover her costs?
