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Yuliya22 [10]
3 years ago
10

A boxed lunch costs $7.01 how much would 9 boxed lunches cost

Mathematics
2 answers:
vova2212 [387]3 years ago
4 0

$63.09

She would have this amount

Shalnov [3]3 years ago
3 0

7.01(9)

It would cost $63.09

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The product of g and 4
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Answer:

4 grams............

Step-by-step explanation:

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The measure of angle A is 4 degrees greater than the measure of angle B. The two angles are complementary. Find the measure for
svetlana [45]
Given: 
Angle A is 4 degrees greater than the measure of Angle B. Both angles are complementary

Complementary angles have a sum of 90°

Angle A = x + 4° ; Angle B = x

x + 4° + x = 90°
2x = 90° - 4°
2x = 86°
x = 86° ÷ 2
x = 43° ANGLE B.

Angle A = x + 4° ⇒ 43° + 4 = 47°

Given:
Angle D is 5 times the measure of Angle E. These angles are supplementary. This means that their sum is 180°

Angle D = 5x ; Angle E = x

5x + x = 180°
6x = 180°
x = 180° ÷ 6
x = 30°  Angle E.

Angle D = 5x = 5(30) = 150°
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3 years ago
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Find the value of x.
bekas [8.4K]
10 - 2x = 120
120 + 10 = 130

130 / 2 = 65

x = 65

2(65) - 10 = 120
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Help me plz I don't get it !!!!!!!!
Alona [7]
Answer: B.

It grows 3 inches per week
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Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

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